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Scilla [17]
3 years ago
10

What is the pH of a solution whose hydronium concentration is 3.5 x 10^(-3) M? Thanks!

Chemistry
1 answer:
ANEK [815]3 years ago
3 0

Answer:

2.46

Explanation:

- log(3.5 *10^-3)

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Calculate the silver ion concentration in a saturated solution of silver(I) sulfate (K sp = 1.4 × 10 –5). 1.5 × 10–2 M 1.4 × 10–
spin [16.1K]

Answer:

3.0x10⁻²M

Explanation:

Silver sulfate, Ag₂SO₄, has a product constant solubility equilbrium of:

Ag₂SO₄(s) ⇄ 2Ag⁺ + SO₄²⁻

When an excess of silver sulfate is added, some Ag₂SO₄ will react producing Ag⁺ and SO₄²⁻ until reach the equilbrium determined for the formula:

ksp = 1.4x10⁻⁵ = [Ag⁺]² [SO₄²⁻]

Assuming the Ag₂SO₄ that react until reach equilibrium is X, we can replace in Ksp expression:

1.4x10⁻⁵ = [Ag⁺]² [SO₄²⁻]

1.4x10⁻⁵ = [2X]² [X]

1.4x10⁻⁵ = 4X³

3.5x10⁻⁶ = X³

0.015 = X

As [Ag⁺] is 2X:

[Ag⁺] = 0.030 = 3.0x10⁻²M

The answer is:

<h3>3.0x10⁻²M</h3>
7 0
3 years ago
Diffrentiate between electrolyric cells and galvanic cells
Scilla [17]
The different is that the galvanic cell converts chemical energy into the electrical energy and the electrolytic cell coverts electrical energy into chemical energy
7 0
3 years ago
Assuming you have 6.24 x 1014 electrons and the surface area of the pail is 0.2 m2, what is the charge density (C/m2)?
pentagon [3]

Answer:

σ = 4.998 E-4 C/m²

Explanation:

  • 1 Coulomb (C) ≡ 6.241509 E18 electrons (e)

∴ # elect = 6.24 E14 elect

charge (Q):

⇒ Q = (6.24 E14 elect)/( 1 C /6.241509 E18 elect) = 9.998 E-5 C

charge density (σ):

  • σ = Q/S

∴ surface area (S) = 0.2 m²

⇒ σ = ( 9.998 E-5 C ) / ( 0.2 m²)

⇒ σ = 4.998 E-4 C/m²

4 0
3 years ago
Give the quantum values of n,l,m and s for nitrogen
sweet [91]
L = 0 to n-1. Hence, it can have values 0, 1, 2. 

<span>m = -l to +l. Hence, it can have values -2, -1, 0, 1, 2 </span>

<span>s = +1/2 and -1/2</span>

4 0
3 years ago
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