Fist law of motion is piece of cake
<span>Things don’t move to get a shake </span>
<span>Second law of ,motion </span>
<span>Is all about the force </span>
<span>If something hits hard </span>
<span>Then the object takes that force </span>
<span>Third of motion is to give you satisfaction </span>
<span>For ever forth mate there is opposite reaction
Hope this helps. :)</span>
Answer:
Explanation:
In the following reaction we have shown an example of aromatic substitution reaction .
C₆H₆ + RCl = C₆H₅R + HCl
This reaction takes place in the presence of catalyst like AlCl₃ which is a lewis acid .
First of all formation of carbocation is made as follows .
RCl + AlCl₃ = R⁺ + AlCl₄⁻
This R⁺ is carbocation which is also called electrophile . It attacks the ring to get attached with it .
C₆H₆ + R⁺ = C₆H₅R⁺H.
The complex formed is unstable , though it is stabilized by resonance effect . In the last step H⁺ is kicked out of the ring . The driving force that does it is the steric hindrance due to presence of two adjacent group of H and R⁺ at the same place . Second driving force is attack by the base AlCl₄⁻ that had been formed earlier . It acts as base and it extracts proton ( H⁺ ) from the ring .
C₆H₅R⁺H + AlCl₄⁻ = C₆H₆ + AlCl₃ + HCl .
The formation of a stable product C₆H₆ also drives the reaction to form this product .
Hi just wanted to say thank you for answering my question and I wanted to help so I believe the answer is A.
Answer:
H3PO4 + 5 HCl → PCl5 + 4 H2O
Explanation:
The given equation is
H3PO4 + HCl = PCl5 + H2O
The above chemical equation has one P atom on both the sides, hence phosphorus is balanced
There are 5 Cl on the RHS but only one Cl on the LHS. On balancing the chlorine, we get -
H3PO4 + 5HCl = PCl5 + H2O
Now, there are 8 hydrogen atom on the LHS but only two on the RHS. On balancing the hydrogen on both the sides, the new equation become
H3PO4 + 5HCl = PCl5 + 4H2O
Let us check for oxygen
Oxygen on LHS = 4 and oxygen on RHS = 4
Thus, the balanced equation is H3PO4 + 5HCl = PCl5 + 4H2O
