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amm1812
3 years ago
7

A sample of gas has a volume of 100.0 L at 135°C. Assuming the pressure remains constant, what is the volume of the gas if its t

emperature decreases to 72.0 °C?
Chemistry
1 answer:
lina2011 [118]3 years ago
8 0

Answer: 84.56L

Explanation:

Initial volume of gas V1 = 100L

Initial temperature T1 = 135°C

Convert temperature in Celsius to Kelvin

( 135°C + 273 = 408K)

Final temperature T2 = 72°C

( 72°C + 273= 345K)

Final volume V2 = ?

According to Charle's law, the volume of a fixed mass of a gas is directly proportional to the temperature.

Mathematically, Charles' Law is expressed as: V1/T1 = V2/T2

100L/408K = V2/345K

To get the value of V2, cross multiply

100L x 345K = V2 x 408K

34500 = V2 x 408K

V2.= 34500/408

V2 = 84.56L

Thus, the volume of the gas becomes 84.56 liters

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Answer:

Well, not always. It depends on where you're doing the boiling. In fact, water will boil at about 202 degrees in Denver, due to the lower air pressure at such high elevations

Explanation:

4 0
3 years ago
The molarity (M) of an aqueous solution containing 29.8 g of sucrose, C12H22O11, in 120 mL of solution is:
Rama09 [41]

Answer:

0.726 mol·L⁻¹

Step-by-step explanation:

c = moles/litres

=====

Moles = 29.8 × 1/342.30

Moles = 0.087 06 mol

=====

Litres = 120 × 1/1000

Litres = 0.120 L

=====

c = 0.087 06/0.120

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5 0
3 years ago
If 200 grams of water is to be heated from 24.0oC to 100.0oC to make a cup of tea, how much heat must be added?
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According to this formula:

Q = M*C*ΔT 

when we have M ( the mass of water) = 200 g 

and C ( specific heat capacity ) of water = 4.18 J/gC

ΔT (the difference in temperature) = Tf - Ti 
     
                                                          = 100 - 24

                                                          = 76°C

So by substitution:


Q = 200 g * 4.18 J/gC * 76 °C

   = 63536 J 

 ∴ the amount of heat which be added and absorbed to raise the temp from 24°C to 100°C is = 63536 J


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3 years ago
How many moles are in 0.0073 kg of tantalum?
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Tantalum is the 73rd element in the periodic table with an atomic mass equal to 180.95 g/mol. To determine the number of moles present in the given mass of tantalum above, we simply divide the mass by the atomic mass. 
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Therefore, there is approximately 0.0403 moles of tantalum in 0.0073 kg. 
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Answer:

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