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Ghella [55]
4 years ago
15

atch the following aqueous solutions with the appropriate letter from the column on the right. 1. 0.14 m MnBr2 A. Lowest freezin

g point 2. 0.12 m CuCl2 B. Second lowest freezing point 3. 0.10 m AlCl3 C. Third lowest freezing point 4. 0.34 m Urea(nonelectrolyte) D. Highest freezing poin
Chemistry
1 answer:
OLEGan [10]4 years ago
6 0

The Lowest freezing point= 0.34 m urea

the highest  freezing point= 0.14m MnBr2

second lowest freezing point= 0.10m  AlCl3

third lowest freezing point= 0.12m CuCl2

Explanation:

The freezing point depression can be calculated from the formula:

T f = i*K *fm ( ΔTf is the freezing point depression, i is van't Hoff factor, Kf is the freezing point depression constant for the solvent

Van't Hoff factor is no of ions involved in reaction, for non electrolytes it is one

T of water = 1.86 degrees kg/ mole

so, 0.14 MnBr2

T= 1.86*3*0.14

    = 0.7812

T of 0.12 CuCl2

T= 1.86*3* 0.12

= 0.6696

T of 0.10 Alcl3

T = 1.86*4*0.10

T= 0.744

  • For 0.34 mole urea

T = 1.86*1*0.34

T = 0.6324

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Plan a chromotography experiment to investigate the colours in an ink​
Usimov [2.4K]

Answer:Step 1: Gather the Needed Materials (coffee Filter, Pencil, Beaker, Water Soluble Pen/marker, Water) Step 2: Cut a Strip of Filter Paper From the Coffee Filter and Using the Marker Draw a Thick Line Near the Bottom of the Filter Paper- About 1/4 Inch From the Bottom. Step 3: Allow the Water to Move Up the Paper for Approx. 5 Minutes and Then Remove the Strip From the Water Step 4: Students Should Identify the Individual Colors in the Chromatogram That Make Up the Markers Unique Mix of Ink.  Step 5: Once Students Have Mastered the Technique Its Time to Put Their Skills to the Test in "The Case of the Celebrity Dog-napping"  Step 7: Write the Ransom Note on a Piece of Filter Paper in One of the Suspect Inks.

Explanation: Chromatography is the physical separation of a mixture into its individual components. This lesson integrates mixtures, solutions & solubility into an activity where students will identify the solute & the solvent. Because chromatography can be used to separate the components of inks & dyes, students are able to identify the unique "recipe" that makes up the mixture of a specific brand of pen. After the students are taught the ink chromatography technique, the fun can continue with a mini forensic investigation, "The Case of the Celebrity Dog-napping".

hopes this helps

6 0
3 years ago
Name the following alkyne.<br> Please help me &lt;3
Alexandra [31]

Answer:

D. 7-methyl-3-octyne

Explanation:

1) Identify the parent chain and name it like an alkane.

• The longest chain of carbons, which consists of the functional group (which is the alkyne group in this case: C≡C).

• There are 8 carbons in the longest chain, so it is called an octane.

2) Now, identify the location of the functional group.

• The location number of the functional group should be as low as possible. Thus although we could count from the right, we start counting from the left since the functional group is closer to the left. From the left, the functional group would be at carbon 8 while from the left, it is on carbon 3.

• Replace 'ane' with 'yne' in octane for the alkyne group.

• This would give us 3-octyne.

3) Lastly, add in the name of the branch.

• Here we have one branch, -CH₃. This is read as methyl.

• Identify the location number of the branch by counting the number of carbons in the same direction as when we counted the location number of the functional group. The methyl branch has a location number of 7.

• Adding the name of the branch before the parent chain, we would arrive at 7-methyl-3-octyne as the IUPAC name of the alkyne.

Further Explanation:

A) This option is incorrect as there are only 8 carbons in the parent chain. Although there are 9 carbons in total, the 9th carbon is taken care of in '7-methyl'.

B) Location number of the functional group should be as low as possible, so start counting the number of carbons from the left!

C) Since the functional group is an alkyne, the word 'octane' should be 'octyne' instead.

8 0
3 years ago
What is the molarity of a NaOH solution if 15.0 mL of the solution is neutralized by 38.5 mL 0.150 M H3PO4 solution?
wlad13 [49]
The solution for this problem is:
Look for the moles of NaOH which is 0.0385 L x 0.150 M = 0.00578 
H3PO4 + 3 NaOH = Na3PO4 + 3 H2O 
moles H3PO4 = 0.00578 / 3 = 0.00193 
M of H3PO4 = 0.00193 mol / 0.0150 L= 0.128 is the molality we are looking for in this problem.
4 0
3 years ago
If the Temperature exerted on a sample of gas is increased from 273K to 410K, and the initial pressure is 1.3317 atm what is the
dsp73

Answer: 2.00 atm

Explanation:

P1/T1 = P2/T2

1.3317/273 = P2/410

P2 = 2.00 atm

8 0
3 years ago
If an equal quantity of heat is transferred to 10.0 g samples of liquid water (C = 4.184 J/g°C), concrete (C = 0.88 J/g°C), asph
qaws [65]

Answer:

The ranking is given as; Water > Asphalt > Concrete > glass > Iron

Explanation:

The trick in solving this question is to assume a constant heat value; in this case i'll be choosing 100 J. Use this value to solve for the temperature difference. from that we can be able to rank the samples in order of their temperatures.

The formular to be used here is the;

H = MCΔT

Where;

H = Heat

M = Mass

C = Heat Capacity

ΔT = Temperature difference

ΔT = H/MC

In water;

ΔT = 100 / (10 * 4.184) = 2.39K

In Concrete;

ΔT = 100 / (10 * 0.88) = 11.36K

In asphalt;

ΔT = 100 / (10 * 0.920) = 10.87K

In glass;

ΔT = 100 / (10 * 0.84) = 11.9K

In iron;

ΔT = 100 / (10 * 0.448) = 22.3K

The samples with least temperature difference would have final temperatures and vice versa.

Our ranking is the given as; Water > Asphalt > Concrete > glass > Iron

7 0
4 years ago
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