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anzhelika [568]
3 years ago
13

Lab Investigator: Chemical reactions cannot be used for what?

Chemistry
2 answers:
yan [13]3 years ago
8 0

C.  Viewing all chemical reaction in a laboratory

hope this helps :)


Murrr4er [49]3 years ago
6 0


viewing any chemical reaction in a labitory
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Given: 2H2O2 → 2H2O + O2 structure of H2O2: H–O–O–H Bond Bond Energy (kJ/mol) O–H 459 O=O 494 O–O 142 Based on the given bond en
ICE Princess25 [194]

Answer:

B. - 210 kJ

Explanation:

<em>∵ ΔHrxn = ∑(bond energies)products - ∑(bond energies)reactants.</em>

  • The bond formation in the products releases energy (exothermic).
  • The bond breaking in the reactants requires energy (endothermic).

The products:

  • H₂O contains 2 O-H (- 459 kJ/mol) bonds.
  • O₂ contain 1 O=O (- 494 kJ/mol) bond.

The reactants:

  • H₂O₂ contain 2 O–H (459 kJ/mol) bonds and 1 O–O (142 kJ/mol) bond.

∵ ΔHrxn = ∑(bond energies)products - ∑(bond energies)reactants.

<em>∴ ΔHrxn = [2 (2 x (O–H bond energy) + (1 x (O=O bond energy)] - 2 [(2 x (O–H bond energy) + (1 x (O–O bond energy)] </em>= [2 (2 x - 459 kJ/mol) + (1 x - 494 kJ/mol)] - 2 [(2 x 459 kJ/mol) + (1 x 142 kJ/mol)] = (- 2330 kJ) + (2120 kJ) = <em>- 210 kJ.</em>

5 0
3 years ago
How much time does it take for a truck to slow down if its acceleration is -15m/s2 and the change in velocity is -30m/s
damaskus [11]

Answer:

2s

Explanation:

Given parameters:

Acceleration of the truck = 15m/s²

change in Velocity  = 30m/s

Unknown:

Time taken for the body to slow down = ?

Solution:

Acceleration is the rate of change of velocity ;

  Acceleration  = \frac{change in velocity}{time}

    time  = \frac{change in velocity }{acceleration}  

Now insert the parameters and solve;

   time  = \frac{30}{15}  = 2s

5 0
3 years ago
What is the concentration in molarity of a solution made using 30.0 grams of CH3OH in 300.0 mL of water?
jasenka [17]
The answer is in the attached photo

4 0
4 years ago
Read 2 more answers
[H3O+] of a 3.0 x 10-2 M NaOH<br> soln?
ikadub [295]
Um what do u mean???????
7 0
3 years ago
HELP PLEASE
WINSTONCH [101]

Answer:

164atm

Explanation:

Given parameters:

Initial pressure  = 150atm

Initial temperature  = 27°C  = 27 + 273 = 300K

New temperature  = 55°C  = 328K

Unknown:

New pressure  = ?

Solution:

At constant volume, the pressure of a given gas varies directly with the absolute temperature.

 Mathematically;

       \frac{P_{1} }{T_{1} }   = \frac{P_{2} }{T_{2} }  

P and T are pressure and temperature values

1 and 2 are the initial and new states

  Insert the parameters and solve;

   \frac{150}{300}   = \frac{P_{2} }{328}  

     300P₂  = 150 x 328

           P₂  = 164atm

4 0
3 years ago
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