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3 years ago

What is a measure between the difference in start and end positions?

Physics

1 answer:

crimeas [40]3 years ago

5 0

Answer:

Displacement

General Formulas and Concepts:

<u>Kinematics</u>

Displacement vs Total Distance

Explanation:

Displacement is the difference between the start position and end position.

Total Distance is the entire distance <em>traveled</em> between the start and end position.

Topic: AP Physics 1 Algebra-Based

Unit: Kinematics

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A mass attached to a spring vibrates back and forth. At maximum displacement, the spring force and the

Svetradugi [14.3K]

ANSWER

Velocity of the mass reaches zero

EXPLANATION

We want to identify what hapens to a mass attached toa a spring at maximum displacement.

When a mass attached to a spring is at its maximum position of displacement, the direction of the mass begins to change. This implies that the velocity of the mass will reach zero.

Hence, at maximum displacement, the velocity of the mass reaches zero.

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1 year ago

You serve a volleyball with a mass of 2.1 kg. The ball leaves your hand with a speed of 30 m/s. The ball has—— energy. Calculate

Slav-nsk [51]

Answer:

945 j

Explanation:

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3 years ago

Which of the following is true about all electromagnetic waves in a vacuum

Helen [10]

Electro waves in a vacuum air is deals with this and electricity when the air and the electricity it makes electro magnets.

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3 years ago

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What is the power of a student that has done a work of 10 joules in 10 seconds

Alla [95]

Answer:

1 Watt

Explanation:

P=W/t

P=10/10

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8 0

3 years ago

A vessel with an unknown volume is filled with 10 kg of water at 90oC. Inspection of the vessel at equilibrium shows that 8 kg o

damaskus [11]

Hey there!

In this case, it is possible to solve this problem by using the widely-known steam tables which show that at 90 °C, the pressure that produces a vapor-liquid mixture at equilibrium is about 70.183 kPa (Cengel, Thermodynamics 5th edition).

Moreover, for the calculation of the volume, it is necessary to calculate the volume of the vapor-liquid mixture, given the quality (x) it has:

$x=\frac{m_{steam}}{m_{total}}$

Thus, since 8 kg correspond to liquid water, 2 kg must correspond to steam, so that the quality turns out:

$x=\frac{2kg}{10kg} =0.20$

Now, at this temperature and pressure, the volume of a saturated vapor is 2.3593 m³/kg whereas that of the saturated liquid is 0.001036 m³/kg and therefore, the volume of the mixture is:

$v=0.001036m^3/kg+0.2(2.3593-0.001036 )m^3/kg=0.4727m^3/kg$

This means that the volume of the container will be:

$V=10kg*0.4727m^3/kg\\\\V=4.73m^3$

Regards!

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2 years ago