The 3rd class lever is the <span>output force always less than the input force, becuase its mechanical advantage is always less than 1. this also due that in a 3rd class lever the effort arm is shorter than the load arm, that is why the output is lower than the input force. but 3rd class lever is a speed multiplier lever</span>
Answer:
Because the force is inversely proportional to the square of the distance
Explanation:
The magnitude of the electrostatic force between two charged particles is given by
where
k is the Coulomb's constant
q1, q2 are the magnitudes of the two charges
d is the distance between the two charges
We observe that the magnitude of the force is inversely proportional to the square of the distance.
Therefore, when the distance changes to
The force will double:
Answer:
Bounce 1 , pass 3, emb2
Explanation:
(By the way I am also doing that question on College board physics page) For the Bounce arrow, since it bumps into the object and goes back, it means now it has a negative momentum, which means a larger momentum is given to the object. P=mv, so the velocity is larger for the object, and larger velocity means a larger kinetic energy which would result in a larger change in the potential energy. Since K=0.5mv^2=U=mgh, a larger potential energy would have a larger change in height which means it has a larger angle θ with the vertical line. Comparing with the "pass arrow" and the "Embedded arrow", the embedded arrow gives the object a larger momentum, Pi=Pf (mv=(M+m)V), it gives all its original momentum to the two objects right now. (Arrow and the pumpkin), it would have a larger velocity. However for the pass arrow, it only gives partial of its original momentum and keeps some of them for the arrow to move, which means the pumpkin has less momentum, means less velocity, and less kinetic energy transferred into the potential energy, and means less change in height, less θangle. So it is Bounce1, pass3, emb2.
I halved the speed of light in vacuum to get the speed of light in the material, since the speed of light in vacuum is twice the speed of light in material.
The index of refraction is essentially the speed of light through a vacuum divided by the speed of light through given medium.
I attached some notes on refraction too, hopefully this helps :D
Answer:
Rifle Momentum=7.77kg*m/s v'= 1.554 m/s
Explanation:
a) m1v1 + m2v2 = m1v1' + m2v2'
0+0 = 0.03*259 + P(rifle momentum)
solve for P
p= 7.77kg*m/s
b) 7.77= 5*v'
v'= 1.554 m/s
