Answer: Hey
B an encyclopedia entry about an experiment
A primary resource is information that was documented during an event that was written about.
Please wait tell you get another answer because im not sure about this
Answer:
Grams of water can be heated from 20.0°C to 75°C using 12500.0 Joules = 54.3 g
Explanation:
Heat required to increase temperature
H = mcΔT
m = mass of material
C = specific heat of material
ΔT = Change in temperature.
Here we need to find how many grams of water can be heated from 20.0°C to 75°C using 12500.0 Joules
That is
H = 12500 J
Specific heat of water, C = 4186 J/kg°C
ΔT = 75 - 20 = 55
Substituting
12500 = m x 4186 x 55
m = 0.0543 kg
m = 54.3 g
Grams of water can be heated from 20.0°C to 75°C using 12500.0 Joules = 54.3 g
Because the ones that have better adaptions survive and spread on the genes for that adaptation
Answer:
1.97 m/s.
Explanation:
From the question,
Using the law of conservation of energy,
The energy stored in the charged plate = Kinetic energy of the mass
1/2(qV) = 1/2mv².......................... Equation 1
Where q = charge, V = voltage, m = mass, v = velocity.
make v the subject of the equation
v = √(qV/m)......................... Equation 2
Given: q = 6.5×10⁻⁶ C, V = 12000 Volts, m = 0.02 kg
Substitute these values into equation 2
v = √(6.5×10⁻⁶×12000 /0.02)
v = √3.9
v = 1.97 m/s.
Answer:
Explanation:
Given
mass of bus along with travelers travelling in North direction is 
speed of bus towards North 
mass of bus travelling in South direction is 
speed of bus 
mass of each Passenger in south moving bus 
Momentum of North moving bus



Momentum with south moving bus


For total momentum to be towards south
should be greater than 0
thus for least value of n


