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Harman [31]
3 years ago
6

What are advantages and disadvantages of using a solar cooker compared to other meanings of cookings?

Physics
1 answer:
drek231 [11]3 years ago
8 0

The advantage of using a solar cooker is that it is Eco-friendly and the disadvantage is that it can be used only under certain conditions.

<h3><u>Explanation:</u></h3>

A solar cooker is used for cooking food without having to use electricity or gas. Instead, the appliance uses heat from the sun to cook food. It is used widely in by people who travel in remote areas or go on trips. But the appliance has limitations of its own too.

ADVANTAGES

  • Using it is friendly to the environment
  • It can be easily assembled without expert assistance
  • No compromise on the quality and taste of foo

DISADVANTAGES

  • Requires sun to function and prepare food
  • Cannot function in winters or monsoon when the sun isn't present
  • Does not retain heat as efficiently and quickly as compared to other cooking appliances
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What time does the full moon rise? A. About Sunrise B. About Noon C. About Sunset D. About Midnight
Lisa [10]

Answer:

The correct option is: c) Sunset

Explanation:

Moon is the permanent natural satellite of the Earth. It orbits around our planet Earth and shows synchronous rotation.  

When Earth is present between the Moon and Sun, the moon appears to be fully illuminated from the Earth, this is called the full moon. <u>All full moons rise about the same time as the sunset.</u>

8 0
3 years ago
Read 2 more answers
A diver wants to jump from a board, the initial height is 10 meters and he wants to reach a horizontal distance of 2 meters. Wha
bulgar [2K]

Answer:

1.4 m/s

Explanation:

The minimum speed will be when the diver's initial velocity is horizontal.

First, find the time it takes for the diver to fall 10 meters.

Given:

Δy = 10 m

v₀ᵧ = 0 m/s

aᵧ = 9.8 m/s²

Find: t

Δy = v₀ t + ½ at²

10 m = (0 m/s) t + ½ (9.8 m/s²) t²

t = 1.43 s

Now find the initial horizontal velocity.

v = (2 m) / (1.43 s)

v = 1.4 m/s

4 0
3 years ago
Question 1 (1 point)
puteri [66]

Answer:

250 N

Explanation:

a =  \frac{vf - vi}{t}

Vf=final velocity

Vi =initial velocity

=70-20/2=25m/s^2

F=ma

=10kg * 25m/s^2

=250N

3 0
3 years ago
A ball is thrown upwards at a velocity of 20.2m/s at what time will the ball reach its highest point
Andre45 [30]
Use the equation
vf = vo + a \times t
plug in the variables for the equation. Use 0 for Vf because at the highest point the velocity would be zero. Use -9.8 for acceleration because that is the speed at which gravity pulls down.
0 = 20.2 + ( - 9.8) \times t
your answer would be 2.06122 seconds.
7 0
3 years ago
A 1100 kg car rounds a curve of radius 68 m banked at an angle of 16 degrees. If the car is traveling at 95 km/h, will a frictio
Mariulka [41]

Answer:

Yes. Towards the center. 8210 N.

Explanation:

Let's first investigate the free-body diagram of the car. The weight of the car has two components: x-direction: towards the center of the curve and y-direction: towards the ground. Note that the ground is not perpendicular to the surface of the Earth is inclined 16 degrees.

In order to find whether the car slides off the road, we should use Newton's Second Law in the direction of x: F = ma.

The net force is equal to F = \frac{mv^2}{R} = \frac{1100\times (26.3)^2}{68} = 1.1\times 10^4~N

Note that 95 km/h is equal to 26.3 m/s.

This is the centripetal force and equal to the x-component of the applied force.

F = mg\sin(16) = 1100(9.8)\sin(16) = 2.97\times10^3

As can be seen from above, the two forces are not equal to each other. This means that a friction force is needed towards the center of the curve.

The amount of the friction force should be 8.21\times 10^3~N

Qualitatively, on a banked curve, a car is thrown off the road if it is moving fast. However, if the road has enough friction, then the car stays on the road and move safely. Since the car intends to slide off the road, then the static friction between the tires and the road must be towards the center in order to keep the car in the road.

5 0
3 years ago
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