Answer:
6. a. friction between a tire and the road
7. c. energy of motion
8. c. the force with which a moving vehicle hits another object
Explanation:
6. As a car moves along the road, the tires push back against the ground. As tires push back against the ground, the road exerts and opposing force to the motion of the tires. This opposing force is the friction between the tires and the road. <u>This opposing force between the tires and the rad is called traction.</u>
So, the answer is a
7. As an object moves, it has energy. <u>This energy due to its motion is called kinetic energy.</u>
So, the answer is c
8. When a moving vehicle hits another object, it exerts a force on the object. The process of the vehicle hitting the other object is called impact and the<u> force exerted on the object is called the force of impact. </u>
So, the answer is c.
Answer:
Explanation:
The process is isothermic, as P V = constant .
work done = 2.303 n RT log P₁ / P₂
= 2.303 x 5 / 29 x 8.3 x 303 log 2 / 1 kJ
= 300.5k J
This energy in work done by the gas will come fro heat supplied as internal energy is constant due to constant temperature.
heat supplied = 300.5k J
specific volume is volume per unit mass
v / m
pv = n RT
pv = m / M RT
v / m = RT / p M
specific volume = RT / p M
option B is correct.
Answer: [B]: The letter, "<em /> I " ; for current; in units of "Amps" .
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A) The friction force while the box is stationary is (the coefficient of static friction)*(the normal force). In this case, the normal force is equal to the gravitational force, or the weight. To move the box, we need a minimum horizontal force that is equal to the friction force. The weight is (500 kg)*(9.81 m/s^2)= 4905 N. So, (0.45)*(4905 N) = 2207.25 N.
b) The acceleration will be the horizontal force - the kinetic friction force (since they act in opposite directions) divided by the mass. Kinetic friction force = (coefficient of kinetic friction)*(normal force or weight).
F(net) = (2207.25 N)-(0.30)(4905 N) = 735.75 N
a = (735.75 N)/(500kg)= 1.4715 m/s^2
Answer:

Explanation:
According to the given reaction,
heat released by thecombustion of 2 molecules of Methanol, 
we know that molecular mass of Methanol, 
∴12 gram of methanol = 
we know 1 mole = 
so,

Heat from the combustion of
:


<u>Now the mass of water that can be heated from 23.5°C to 88.2°C :</u>


