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3 years ago

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Papessa [141]3 years ago

6 0

) 5 -5 1 2 3 4 5 Other than at t = 0, when is the velocity of the object equal to zero? 1. 5.0 s 2. 4.0 s 3. 3.5 s 4. At no other time on this graph. correct 5. During the interval from 1.0 s to 3.0 s. Explanation: Since vt = Z t 0 a dt, vt is the area between the acceleration curve and the t axis during the time period from 0 to t. If the area is above the horizontal axis, it is positive; otherwise, it is negative. In order for the velocity to be zero at any given time t, there would have to be equal amounts of positive and negative area between 0 and t. According to the graph, this condition is never satisfied. 005 (part 1 of 1) 0 points Identify all of those graphs that represent motion at constant speed (note the axes carefully). a) t x b) t v c) t a d) t v e) t a

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A traveling electromagnetic wave in a vacuum has an electric field amplitude of 98.9 V/m . Calculate the intensity ???? of this

Pani-rosa [81]

Answer:

$intensity = 12.98 W/m^2$

$Energy = 3.93 J$

Explanation:

As we know that the magnitude of electric field intensity is given as

$E = 98.9 V/m$

now we know that intensity of the wave is given as the product of energy density and speed of the wave

$intensity = \frac{1}{2}\epsilon_0 E^2 c$

$intensity = \frac{1}{2}(8.85 \times 10^{-12})(98.9)^2(3\times 10^8)$

$intensity = 12.98 W/m^2$

so intensity is the energy flow per unit area per unit of time

so the energy that flows through the area of 0.0259 m^2 in 11.7 s is given as

$Energy = Area \times time \times intensity$

$Energy = 0.0259(11.7)(12.98)$

$Energy = 3.93 J$

7 0

3 years ago

Q7:<br> A 4 kg toy is lifted off the ground and falls at 3 m/s. What is the toy's energy?

alexandr1967 [171]

Answer:

The toy's energy is 18 J.

Explanation:

We have, a 4 kg toy is lifted off the ground and falls at 3 m/s. It is required to find toy's energy.

The toy will have kinetic energy due to its motion. The energy is given by :

$E=\dfrac{1}{2}mv^2\\\\E=\dfrac{1}{2}\times 4\times 3^2\\\\E=18\ J$

So, the toy's energy is 18 J.

7 0

3 years ago

Need help with number 6 and 7 please

elena-14-01-66 [18.8K]

358 rocks, critical thinking

4 0

3 years ago

What is the speed of a beam of electrons when under the simultaneous influence of E = 1.64×104 V/m B = 4.60×10−3 T Both fields a

andrezito [222]

Answer: v = 3.57×10^6 m/s; R = 4.42×10^-3m; T = 7.78×10^-9 s

Explanation:

Magnetic force(B) = 4.60×10^-3 T

Electric force(E) = 1.64×10^4 V/m

Both forces having equal magnitude ;

Magnetic force = electric force

qvB = qE

vB = E

v = (1.64×10^4) ÷ (4.60×10^-3)

v = 3.57×10^6 m/s

2.) Assume no electric field

qvB = ma

Where a = v^2 ÷ r

R = radius

a = acceleration

v = velocity

qvB = m(v^2 ÷ R)

R = (m×v) ÷ (|q|×B)

q=1.6×10^-19C

m = 9.11×10^-31kg

R = (9.11×10^-31 * 3.57×10^6) ÷ (1.6×10^-19 * 4.6×10^-3)

R = 32.5227×10^-25 ÷ 7.36×10^-22

R = 4.42×10^-3m

3.) period(T)

T = (2*pi*R) ÷ v

T = (2* 4.42×10^-3 * 3.142) ÷ (3.57×10^6)

T = (27.775×10^-3) ÷(3.57×10^6)

T = 7.78×10^-9 s

6 0

4 years ago

Which statement places events during the Space Race in the correct order from the earliest to the most recent?

leva [86]

Answer:

3,1,4,2

Explanation:

3 0

3 years ago

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