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1 year ago

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What are the fastest spinning objects known in the universe?

1 answer:

Sergio039 [100]1 year ago

8 0

1) neuron stars

2) centrifugal force

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Einstein's equivalence principle says that __________. Einstein's equivalence principle says that __________. everyone measures

ad-work [718]

Answer:

Einstein's equivalence principle says that __________.

the effects of gravity are exactly equivalent to the effects of acceleration

Explanation:

The equivalence principle is one of the fundamental laws of physics, as enunciated by Einstein. It categorically states that the gravitational and inertial forces are of a similar nature. In physics, a gravitational acceleration is the acceleration of an object in a free fall within a space. The importance of Einstein's Equivalence Principle is explained by his theory of general relativity. This theory states that mass is the same, whether inertial or gravitational.

4 0

3 years ago

A california condor is sitting on the top branch of a redwood tree and has a GPE of 12,100 J. If the condor has a mass of 8kg, w

DanielleElmas [232]

Answer:

william h. seward secured the purchase of alaska from:

Explanation:

3 0

3 years ago

A tightrope walker wants to know the tension used to support the rope that is suspended between two poles. The rope is 18 m long

Alla [95]

Answer:

T = 29.6 N

Explanation:

length of the rope is

L = 18 m

mass of the rope is

m = 12 kg

now we have

mass per unit length of the rope is given as

[te]\lambda = \frac{12 kg}{18 m}[/tex]

now time taken by wave to reach from end to other

$t = \frac{L}{v}$

$2.7 s = \frac{18}{v}$

$v = 6.67 m/s$

now we have

$v = \sqrt{\frac{T}{\lambda}}$

$6.67 = \sqrt{\frac{T}{0.67}}$

so we will have

$T = 29.6 N$

5 0

4 years ago

If you push a crate horizontally with 100 N across a 10 m factory floor and the friction between the crate and the floor is a st

erik [133]

Answer:

300 J

Explanation:

First of all, we need to calculate the net force acting on the crate, which is given by:

$F_{net} = F-F_f$

where

F = 100 N is the horizontal push

$F_f = 70 N$ is the force of friction

Substituting,

$F_{net}=100 - 70 = 30 N$

Now we can calculate the net work done on the crate:

$W=F_{net}d$

where

d = 10 m is the displacement

Substituting,

$W=(30)(10)=300 J$

According to the work-energy theorem, the kinetic energy gained by the crate is equal to the work done on it: therefore, the answer is 300 J.

4 0

3 years ago

A circle has a radius of 10 inches. Find the approximate length of the arc intersected by a central angle of mc001-1. Jpg 6. 67

Andrei [34K]

The approximate length of the arc intersected by the central angle is 20.94 inches.

The given parameters:

<em>Radius of the circle, r = 10 inches</em>
<em>Central angle, </em> $\theta = \frac{2\pi }{3} \ rad$ <em />

<em />

The approximate length of the arc intersected by the central angle is calculated as follows;

S = rθ

where;

<em>S is the length of the arc</em>

Substitute the given parameters and solve for the length of the arc

$S = 10 \ in \times \frac{2\pi }{3} \\\\S = 20.94 \ inches$

Thus, the approximate length of the arc intersected by the central angle is 20.94 inches.

<em>Your question is not complete, find the complete question below:</em>

A circle has a radius of 10 inches. Find the approximate length of the arc intersected by a central angle of $\frac{2\pi}{3}$ .

Learn more about length of arc here: brainly.com/question/2005046

5 0

3 years ago