Answer:
Mole percent of 
in solution is 1.71%
Explanation:
Number of moles of a compound is the ratio of mass to molar mass of the compound.
Molar mass of = 110.98 g/mol
Molar mass of 
= 18.02 g/mol
Density is the ratio of mass to volume
So, mass of 60.0 mL of water = 
Hence, 6.50 g of = 
of = 0.0586 moles of
60.8 g of = 
of = 3.37 moles of
So, mole percent of in solution = \frac{n_{CaCl_{2}}}{n_{total}}\times 100% = 
% = 1.71%
Answer:
The best reagents that are used for the conversion of ethylbenzene to (2-bromoethyl)benzene is shown in the first diagram attached.
Explanation:
Concepts and reason
The concept used to solve this problem is by using the given reagents, possible products will be formed in each step and then label it exactly in the given boxes in order to form the exact product.
Here, the starting reactant is ethyl benzene and the final product is (2-bromoethyl)benzene.
Fundamentals
Bromine molecule is used for bromination of alkene. Trans addition takes place.
Addition of HBr to the double bond forms an alkyl bromide.
Potassium tertiary butoxide is a sterically hindered base.
Bromination of alkane in the presence of sunlight gives radical substitution.
NBS (N-bromosuccinimide) is used for the allylic bromination.
The reaction is as shown in the second attachment(pictures 2,3 and 4).
Answer:
1.1 × 10² g
Explanation:
First, we will convert 1.0 L to cubic centimeters.
1.0 L × (10³ mL/1 L) × (1 cm³/ 1 mL) = 1.0 × 10³ cm³
The density of water is 1.0 g/cm³. The mass corresponding to 1.0 × 10³ cm³ is:
1.0 × 10³ cm³ × (1.0 g/cm³) = 1.0 × 10³ g
1 mole of water (H₂O) has a mass of 18 g, consisting of 2 g of H and 16 g of O. The mass of Hydrogen in 1.0 × 10³ g of water is:
1.0 × 10³ g H₂O × (2 g H/18 g H₂O) = 1.1 × 10² g
Essential for survival growth and reproduction
Answer:
Option D. 230 J
Explanation:
We'll begin by calculating the temperature change of the iron. This can be obtained as follow:
Initial temperature (T₁) = 50 °C
Final temperature (T₂) = 75 °C
Change in temperature (ΔT) =?
ΔT = T₂ – T₁
ΔT = 75 – 50
ΔT = 25 °C
Thus, the temperature change of the iron is 25 °C.
Finally, we shall determine the amount of heat energy used. This can be obtained as follow:
Mass (M) = 20 g
Change in temperature (ΔT) = 25 °C
Specific heat capacity (C) = 0.46 J/gºC
Heat (Q) =?
Q = MCΔT
Q = 20 × 0.46 × 25
Q = 230 J
Thus, the amount of heat used was 230 J
