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ValentinkaMS [17]
3 years ago
11

If f(x)=4x3+Ax2+5x−5 and f(2)=3​, what is the value of​ A?

Mathematics
1 answer:
Luba_88 [7]3 years ago
6 0
The value of x is 24
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Given that f.x 3x-2 over x+1 g[x] x +5 evaluate f[-4] and gf [-2]
Jobisdone [24]

The value of f[ -4 ] and g°f[-2] are \frac{14}{3} and 13 respectively.

<h3>What is the value of f[-4] and g°f[-2]?</h3>

Given the function;

  • f(x) = \frac{3x-2}{x+1}
  • g(x)=x+5
  • f[ -4 ] = ?
  • g°f[ -2 ] = ?

For f[ -4 ], we substitute -4 for every variable x in the function.

f(x) = \frac{3x-2}{x+1}\\\\f(-4) = \frac{3(-4)-2}{(-4)+1}\\\\f(-4) = \frac{-12-2}{-4+1}\\\\f(-4) = \frac{-14}{-3}\\\\f(-4) = \frac{14}{3}

For g°f[-2]

g°f[-2] is expressed as g(f(-2))

g(\frac{3x-2}{x+1}) =  (\frac{3x-2}{x+1}) + 5\\\\g(\frac{3x-2}{x+1}) =  \frac{3x-2}{x+1} + \frac{5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{3x-2+5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{8x+3}{x+1}\\\\We\ substitute \ in \ [-2] \\\\g(\frac{3x-2}{x+1}) =  \frac{8(-2)+3}{(-2)+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{-16+3}{-2+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{-13}{-1}\\\\g(\frac{3x-2}{x+1}) =  13

Therefore, the value of f[ -4 ] and g°f[-2] are \frac{14}{3} and 13 respectively.

Learn more about composite functions here: brainly.com/question/20379727

#SPJ1

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PLEASE HELP WITH THESE 4 PROBLEMS
Marizza181 [45]

Answer:

  • y = -5/2x + 5
  • y = 2x -1
  • y = 24/11
  • y = 4x + 4

Step-by-step explanation:

To solve for y, subtract the x-term and divide by the coefficient of y.

5x +2y = 10

  2y = -5x +10

  y = -5/2x + 5

__

2y -4x = -2

  2y = 4x -2

  y = 2x -1

__

7y +4y = 24

  y = 24/11

We assume there is a typo, but cannot tell what it is. Use the same method as described and demonstrated for the other problems.

__

-2x +1/2y = 2

  1/2y = 2x +2

  y = 4x +4

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3 years ago
What are the polar coordinates for (-7, 7)?​
scZoUnD [109]

Answer:

The polar form of (7, - 7) is (r, θ) = (7√2, - π/4)

Step-by-step explanation:

3 0
3 years ago
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