A deep space probe travels in a straight line at a constant speed of over 16,000 m/s. Assuming there is no friction in space, if
1 answer:
You might be interested in
Answer:
Proof in explanataion
Explanation:
The basic dimensions are as follows:
MASS = M
LENGTH = L
TIME = T
i)
Given equation is:
where,
H = height (meters)
u = speed (m/s)
g = acceleration due to gravity (m/s²)
Sin Ф = constant (no unit)
So there dimensions will be:
H = [L]
u = [LT⁻¹]
g = [LT⁻²]
Sin Ф = no dimension
Therefore,
<u>[L] = [L]</u>
Hence, the equation is proven to be homogenous.
ii)
where,
F = Force = Newton = kg.m/s² = [MLT⁻²]
G = Gravitational Constant = N.m²/kg² = (kg.m/s²)m²/kg² = m³/kg.s²
G = [M⁻¹L³T⁻²]
m₁ = m₂ = mass = kg = [M]
r = distance = m = [L]
Therefore,
<u>[MLT⁻²] = [MLT⁻²]</u>
Hence, the equation is proven to be homogenous.
Answer:
E=6.91 N/C
Explanation:
Given that
Linear Charge density ,λ = 5 nC/m
Distance ,R= 13 m
We know that formula for long wire to find electric field
E=Electric field
R=Distance
εo=8.85 x 10⁻¹² C²/N.m²
λ=Linear Charge density
Now by putting the values
E=6.91 N/C
Therefore the electric filed at distance 13 m will be 6.91 N/C