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Alisiya [41]
4 years ago
10

A deep space probe travels in a straight line at a constant speed of over 16,000 m/s. Assuming there is no friction in space, if

a loose part were released from the spacecraft without a push in any direction, what would happen to it?
A. It would slowly coast to a stop.
B. It would head off on its own trajectory.
C. It would stop immediately as soon as it was no longer in contact with the probe.
D. It would continue along with the spacecraft.

Help!!!!!!!!!! Please!!!!! Im desperate!!!!!!!!!
Physics
1 answer:
diamong [38]4 years ago
3 0

Answer:

I believe that the answer is d.

Explanation:

Because there is nothing to make the aircraft accelerate or decelerate, it is going to stay in constant motion with no acceleration.

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An alert physics student stands beside the tracks as a train rolls slowly past. He notes that the frequency of the train whistle
Dovator [93]

Answer:The velocity of the train is 3.84m/s

Explanation:

According to the Doppler effect, if the source is moving towards you then the apparent frequency of the sound emitted by the source is higher and if the source is moving away from you then the apparent frequency of the sound emitted by the source is smaller.

This is given by:

fo = V +-Vo/ V +-Vo × source

Where fo= observed frequency

V= velocity of sound

Vo= vo it of the observer

fsource= frequency the source

Given:

Observed frequency of the approaching train fo1= 452Hz

The observed frequency of train= fo2= 442Hz

Velocity of sound= 334m/s

Velocity of source=?

Train approaching the observer is given by:

fo1= V/(V - Vs)× source ...eq1

Train passes the student is given by:

fo2= V/(V - Vs)×source ...eq2

Divide eq1 by eq2

452/442 = (343+Vs)/(343 - Vs)

1.02 =(343+Vs)/(343 -Vs)

Cross multiply

1.02(343- Vs) = 343 + Vs

350.76 - 1.02Vs = 343 + Vs

Collecting like terms

350.76 -343= 1.02Vs+ Vs

7.76 = 2.02Vs

Vs= 7.76/2.02

Vs= 3.84m/s

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3 years ago
What is the potential energy of a one kilogram box of chocolates hidden on a
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Answer:

um it well it will be 19.6 d) 9.8 J

Explanation:

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3 years ago
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An object of mass 0.50 kg is transported to the surface of Planet X where the object's weight is measured to be 20 N. The radius
vovangra [49]

Explanation:

The free fall acceleration is:

F = ma

20 N = (0.50 kg) a

a = 40 m/s²

The mass of Planet X is:

F = GMm / r²

20 N = (6.67×10⁻¹¹ Nm²/kg²) M (0.50 kg) / (4.0×10⁶ m)²

M = 9.6×10²⁴ kg

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A car, moving along a straight stretch of highway,
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What happens when aluminum fills its valence shell?
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I beileve the answer is B
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