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Alisiya [41]
3 years ago
10

A deep space probe travels in a straight line at a constant speed of over 16,000 m/s. Assuming there is no friction in space, if

a loose part were released from the spacecraft without a push in any direction, what would happen to it?
A. It would slowly coast to a stop.
B. It would head off on its own trajectory.
C. It would stop immediately as soon as it was no longer in contact with the probe.
D. It would continue along with the spacecraft.

Help!!!!!!!!!! Please!!!!! Im desperate!!!!!!!!!
Physics
1 answer:
diamong [38]3 years ago
3 0

Answer:

I believe that the answer is d.

Explanation:

Because there is nothing to make the aircraft accelerate or decelerate, it is going to stay in constant motion with no acceleration.

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What is the precision for each measurement for the online simulation. What would be the precision for force
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Answer:

Unit of precision for force is the Newton.

Explanation:

It is the official unit used to describe force in science and mostly abbreviated with the symbol N.

4 0
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Is the maximum displacement of a point on a vibrating body or wave.
Georgia [21]
The correct answer is amplitude
7 0
3 years ago
I NEED HELP ASAP!!!
alekssr [168]

Answer:

B) 3.6x 10_6 N/C or D)2.8 x105 N/C

7 0
3 years ago
In a crash test, a truck with mass 2100 kg traveling at 22 m/s smashes head-on into a concrete wall without rebounding. The fron
slega [8]

Answer:

a)   v_average = 11 m / s, b)  t = 0.0627 s

, c)    F = 7.37 10⁵ N

, d)   F / W = 35.8

Explanation:

a) truck speed can be found with kinematics

         v² = v₀² - 2 a x

The fine speed zeroes them

           a = v₀² / 2x

           a = 22²/2 0.69

           a = 350.72 m / s²

The average speed is

           v_average = (v + v₀) / 2

           v_average = (22 + 0) / 2

           v_average = 11 m / s

b) The average time

          v = v₀ - a t

          t = v₀ / a

          t = 22 / 350.72

          t = 0.0627 s

c) The force can be found with Newton's second law

             F = m a

             F = 2100 350.72

             F = 7.37 10⁵ N

.d) the ratio of this force to weight

             F / W = 7.37 10⁵ / (2100 9.8)

             F / W = 35.8

.e) Several approaches will be made:

- the resistance of air and tires is neglected

- It is despised that the force is not constant in time

- Depreciation of materials deformation during the crash

5 0
3 years ago
A garage door opener has a power rating of 350 watts.
Lelechka [254]
We Know, Power = Energy/Time
Substitute the known value. which is P = 350 watt, & T = 30 sec
350 = E/30 
E = 350 * 30
E = 1050 Joules.

So, your answer is 1050 Joules.
Hope this helps! Keep studying! 
6 0
3 years ago
Read 2 more answers
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