Ah hah ! There's an easy way and a hard way to do this one.
If it's OK with you, I'm gonna do it the easy way, and not even
talk about the hard way !
First, let's look at a few things in this question.
-- "gravitational force between a planet and a mass"
This is just a complicated way to say "How much does the mass weigh ?"
That's what we have to find.
-- If we know the mass, how do we find the weight ?
Multiply the mass by the acceleration of gravity there.
Weight = (mass) x (gravity) .
-- Do we know the acceleration of gravity on this dark mysterious planet ?
We do if we read the second line of the question !
It's right there ... 8.8 m/s² .
-- We know the mass. We know gravity. And we know that
if you multiply them, you get the weight (forced of gravity).
I'm pretty sure that you can do the rest of the solution now.
weight = (mass) x (gravity)
Weight = (17 kg) x (8.8 m/s²)
Multiply them:
Weight = 149.6 kg-m/s²
That complicated-looking unit is the definition of a Newton !
So the weight is 149.6 Newtons. That's the answer. It's choice-A.
It's about 33.6 pounds.
When this mass is on the Earth, it weighs about 37.5 pounds.
But when it's on this planet, it only weighs about 33.6 pounds.
That's because gravity is less on this planet. (8.8 there, 9.8 on Earth)
Use the power and R1 to find the voltage of the battery
P = V²/R
V = √(PR) = √(36.0 W)(25.0 ohm) = 30 V
Now find the equivalent resistance of the new configuration
R_equivalent = R1 + R2 = 40 ohm
Now find the power (energy rate)
P = V²R = (30 V)²/(40 ohm) = 22.5 W
Explanation:
the vector of the coordinates is
11+13 = 24 m East
7 m North
Answer:
a) x=63.0 or 6.3cm
b) x=116.0 or 11.6cm
Explanation:
a).
The elastic potential energy is modeling by equation :
b).
The work energy theorem explain which work is done in this case. the motion began from the rest so K1=K2 equal zero, Ug1 is no yet done and U2is also zero because is the potential energy
Solving for x
The negative is discard so
x=0.116m