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2 years ago

Which type of wave has particles moving in an elliptical or circular motion?

Physics

2 answers:

balu736 [363]2 years ago

7 0

$\huge\bold\purple{answer}$

Option A : surface

A surface wave is a wave in which particles of the medium undergo a circular motion.

mote1985 [20]2 years ago

6 0

$\huge \rm༆ Answer ༄$

The Correct choice is ~

$\sf \boxed{ \sf surface \: \: wave}$

_________________________________

$\\ \\ \\ \\ \\ \\$

$꧁ \:\large \cal{Kaul}\: ꧂$

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A 75 kg Spider Man running at 3.0 m/s jumps onto a trash can lid that has a mass of 10kg and that is already moving in the same

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In order to find the final velocity of the skier and the trash can lid, we may apply the principle of conservation of momentum, which states that the total momentum of a system remains constant. Mathematically, in this case:
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3 years ago

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When the activation energy of an exothermic reaction decreases at a given temperature, the reaction rate increases because the _

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3 years ago

25. Explain why the speed of sound is faster in solids than in gases. Include two other factors Chapter 17 says the speed of sou

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3 years ago

What is the metric unit of measuring the volume of liquids?

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3 years ago

A silver wire has a cross sectional area a = 2.0 mm2. a total of 9.4 × 1018 electrons pass through the wire in 3.0 s. the conduc

marta [7]

This problem uses the relationships among current I, current density J, and drift speed vd. We are given the total of electrons that pass through the wire in t = 3s and the area A, so we use the following equation to to find vd, from J and the known electron density n, so:

$v_{d} = \frac{J}{n\left | q \right |}$

The current I is any motion of charge from one region to another, so this is given by:

 $I = \frac{\Delta Q}{\Delta t} = \frac{9.4x1018electrons}{3s} = 3189.73(A)$

The magnitude of the current density is:

$J = \frac{I}{A} = \frac{3189.73}{2x10^{-6}} = 1594.86(A/m^{2})$

Being:

$A=2mm^{2} = 2x10^{-6}m^{2}$

Finally, for the drift velocity magnitude vd, we find:

 $v_{d} = \frac{1594.86}{5.8x1028\left |1.60x10^{-19}|\right } = 1.67x10^{18}(m/s)$

Notice: The current I is very high for this wire. The given values of the variables are a little bit odd

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3 years ago