Answer:
20N
Explanation:
Force applied by Samantha = 10N
Force applied by Emily = 10N
Since both Samantha pushes the box of textbook in the same direction; their forces are additive.
Net force applied on box = Force applied by Samantha + Emily
Force is a pull or push on a body
Net force = 10N + 10N = 20N
Answer:i think they do i dont understand your question it does not make sence
Explanation:
I believe it is henry Moseley he designed it in 1900
<span>The friction force ( µ . N ) must be enough to counter the gravity force ( m . g )
The Normal force from the rotating wall is the centripetal force = mv^2 / r
so with the lowest coefficient of friction ( 0.4 )
0.4 . v^2 / 2.5 = g
v^2 = 2.5 . 9.8 / 0.4
v = 7.83 m/s
T = 5Ď€ / 7.83 = 2.007 s
f = 0.5 Hz = 30 rpm</span>
Answer:
51.54 m/s
Explanation:
Applying,
Law of conservation of momentum,
Total momentum before collision = Total momentum after collision
mu+m'u' = mv+m'v'.................... Equation 1
Where m = mass of the head of the golf club, m' = mass of the gulf ball, u = initial velocity of the head of the gulf club, u' = initial velocity of the gulf ball, v = final velocity of the head of a gulf club, v' = final velocity of the gulf ball
From the question,
Given: m = 151 g = 0.151 kg, u = 43.9 m/s, m' = 46 g = 0.046 kg, u' = 0 m/s (at rest), v = 28.2 m/s
Substitute these values into equation 1
0.151(43.9)+0.046(0) = 0.151(28.2)+0.046(v')
solve for v'
6.6289+0 = 4.2582+0.046v'
0.046v' = 6.6289-4.2582
0.046v' = 2.3707
v' = 2.3707/0.046
v' = 51.54 m/s