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AURORKA [14]
2 years ago
13

from his playhouse, a child walks 11 m east, then 7 m north, then 13 m east. what is the direction of the child's displacement f

rom his playhouse?
Physics
1 answer:
lana [24]2 years ago
7 0

Explanation:

the vector of the coordinates is

11+13 = 24 m East

7 m North

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Movies and TV shows sometimes portray a person being thrown backwards a sizable distance as a result of being struck by a bullet
MAXImum [283]

Answer:

 R = 4.24 x 10⁻⁴ m

Explanation:

given,

mass of the person = 60.3-kg

mass of the bullet = 10 gram = 0.01 Kg

velocity of bullet = 389 m/s

angle made with the horizontal = 45°

using conservation of momentum.

M v  + m u  = ( M + m ) V

60.3 x 0 + 0.01 x 389 = (60.3 + 0.01) V

V = \dfrac{3.89}{60.31}

V = \dfrac{3.89}{60.31}

V = 0.0645 m/s

for calculation of range

R = \dfrac{V^2sin 2 \theta}{g}

R = \dfrac{0.0645^2sin 2 (45^0)}{9.8}

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the distance actor fall is  R = 4.24 x 10⁻⁴ m

6 0
3 years ago
NEED THIS ASAP
horrorfan [7]

Answer:

Energy is essentially work done by an object or on object.

From,

W = Fd

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from,

K. E = 1/2mv²

Energy is directly proportional to mass.

P. E = mgh

Energy is directly proportional to mass.

H = mc∆T

Energy is directly proportional to mass.

Thus increasing mass will increase the energy also imparted on another object since all the above eqns show that relationship.

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m1u²1 + m2u²2 = m1v²1 + m2v²2

The relationship is the same that the greater mass the greater the impact.

5 0
2 years ago
Suzie skydiver, who weighs 500 n, reaches terminal velocity of 90 km/h. the air resistance on suzie is then
masha68 [24]
<span>Weight of the skydiver m = 500 N
 Terminal velocity V = 90 km/h
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7 0
3 years ago
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_ method is used to remove soluble impurities. ​
anygoal [31]

\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the Concept of the Methods of Separation.

Evaporation and Decantation are the process which can be easily used to remove the Soluble Impurities.

5 0
2 years ago
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In one of the original Doppler experiments, a tuba was played at a frequency of 64.0 Hz on a moving flat train car, and a second
wolverine [178]

Answer:

 f_{beat} = 1.64\ Hz

Explanation:

given,

frequency of tuba.f = 64 Hz

Speed of train approaching, v = 8.50 m/s

beat frequency = ?

using Doppler's effect formula

 f' = f(\dfrac{v}{v-v_s})

v_s is the velocity of the source

v is the speed of sound, v = 340 m/s

now,

 f' = 64\times (\dfrac{340}{340 - 8.50})

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now, beat frequency is equal to

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 f_{beat} = 1.64\ Hz

hence, beat frequency is equal to 1.64 Hz

3 0
3 years ago
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