Answer:
Asteroids
Explanation:
Asteroids are the small and large block of rocks that are found to be scattering space. There are numerous asteroids present in the asteroid belt which is located between the planet of Mars and Jupiter. These range from a few meters to hundreds of kilometers. They move so rapidly, at about 80,000 km/hr and there occurs constant collision with one another. These asteroids sometimes enter into the atmosphere of earth, which can cause a great mass extinction event.
These are believed to be the remnants particles that are present in space right after the formation of the solar system.
I think the answer is b. compaction
The speed of the second mass after it has moved ℎ=2.47 meters will be 1.09 m/s approximately
<h3>
What are we to consider in equilibrium ?</h3>
Whenever the friction in the pulley is negligible, the two blocks will accelerate at the same magnitude. Also, the tension at both sides will be the same.
Given that a large mass m1=5.75 kg and is attached to a smaller mass m2=3.53 kg by a string and the mass of the pulley and string are negligible compared to the other two masses. Mass 1 is started with an initial downward speed of 2.13 m/s.
The acceleration at which they will both move will be;
a = (
-
) / (
+
)
a = (5.75 - 3.53) / (5.75 + 3.53)
a = 2.22 / 9.28
a = 0.24 m/s²
Let us assume that the second mass starts from rest, and the distance covered is the h = 2.47 m
We can use third equation of motion to calculate the speed of mass 2 after it has moved ℎ=2.47 meters.
v² = u² + 2as
since u =0
v² = 2 × 0.24 × 2.47
v² = 1.1856
v = √1.19
v = 1.0888 m/s
Therefore, the speed of mass 2 after it has moved ℎ=2.47 meters will be 1.09 m/s approximately
Learn more about Equilibrium here: brainly.com/question/517289
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A. Jenna because an optimistic person always has a healthier look in life!
Answer:
![v = 4.375\,\frac{m}{s}](https://tex.z-dn.net/?f=v%20%3D%204.375%5C%2C%5Cfrac%7Bm%7D%7Bs%7D)
Explanation:
The situation of the system Ryan - merry-go-round is modelled after the Principle of the Angular Momentum Conservation:
![(350\,kg\cdot m^{2})\cdot (1.5\,\frac{rad}{s} ) - (2\,m)\cdot (60\,kg)\cdot v = 0\,kg\cdot \frac{m^{2}}{s}](https://tex.z-dn.net/?f=%28350%5C%2Ckg%5Ccdot%20m%5E%7B2%7D%29%5Ccdot%20%281.5%5C%2C%5Cfrac%7Brad%7D%7Bs%7D%20%29%20-%20%282%5C%2Cm%29%5Ccdot%20%2860%5C%2Ckg%29%5Ccdot%20v%20%3D%200%5C%2Ckg%5Ccdot%20%5Cfrac%7Bm%5E%7B2%7D%7D%7Bs%7D)
The initial speed of Ryan is:
![v = 4.375\,\frac{m}{s}](https://tex.z-dn.net/?f=v%20%3D%204.375%5C%2C%5Cfrac%7Bm%7D%7Bs%7D)