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Snezhnost [94]
3 years ago
7

A 1.00- and a 2.00- resistor are in parallel. What is the equivalent single resistance? ​

Physics
1 answer:
pochemuha3 years ago
4 0

Answer: R=2/3 ohms

Explanation:

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1.Which statement is true when two objects are 20 miles apart but one is much bigger?
Paha777 [63]

1. C.  Gravitational attraction exists between the two objects.

Explanation:

Gravitational attraction is always exerted between two objects which have mass, and its magnitude is given by:

F=G\frac{m_1 m_2}{r^2}

where G is the gravitational constant, m1 and m2 the masses of the two objects, and r the separation between them. Since the two objects have for sure non-zero masses m1 and m2, even if they are 20 miles apart, the value of the gravitational attraction F is non-zero, so the correct answer is C.


2. D.  Two atoms come together to form a molecule.

Explanation:

this outcome is actually caused by the electrostatic forces between the two atoms, not by gravitational force. In fact, gravitational force becomes relevant only when the masses of the two objects involved are large enough: this is the case for planets, stars, galaxies, and objects in the universe. However, two atoms have very small masses, so the gravitational force between them is really negligible. On this smaller scales, the electrostatic force is much stronger than the gravitational force, so the electrostatic force is the real responsible for the formation of bonds between atoms.

7 0
3 years ago
Read 2 more answers
At an air show, a stunt pilot performs a vertical loop-the-loop in a circle of radius 3.63 x 103 m. During this performance the
san4es73 [151]

Answer:

189 m/s

Explanation:

The pilot will experience weightlessness when the centrifugal force, F equals his weight, W.

So, F = W

mv²/r = mg

v² = gr

v = √gr where  v = velocity, g = acceleration due to gravity = 9.8 m/s² and r = radius of loop = 3.63 × 10³ m

So, v = √gr

v = √(9.8 m/s² × 3.63 × 10³ m)

v = √(35.574 × 10³ m²/s²)

v = √(3.5574 × 10⁴ m²/s²)

v = 1.89 × 10² m/s

v = 189 m/s

5 0
3 years ago
How high is an object lifted if the total work done on it is 125 J and the force required to lift the object is 25 N? Use the eq
mixas84 [53]
The answer would be C. 5m
This is because to find d, you would need to divide W (125 J) by F (25 N).
Hope this helps!
8 0
3 years ago
A proposed space station consists of a circular tube that will rotate about its center (like a tubular bicycle tire), Fig. 5–39.
Trava [24]

Answer:

1742.24106 revolutions per day

Explanation:

v = Velocity

d = Diameter = 1.1 km

r = Radius = \dfrac{d}{2}=\dfrac{1.1}{2}=0.55\ km

g = Acceleration due to gravity = 9.81 m/s²

g = 0.9 g

The centrifugal force will balance the gravitational force

F_c=mg\\\Rightarrow \dfrac{mv^2}{r}=m0.9g\\\Rightarrow v=\sqrt{\dfrac{0.9gmr}{m}}\\\Rightarrow v=\sqrt{0.9gr}\\\Rightarrow v=\sqrt{0.9\times 9.81\times 0.55\times 10^3}\\\Rightarrow v=69.68464\ m/s

\dfrac{1}{T}=\dfrac{v}{2\pi r}\\\Rightarrow \dfrac{1}{T}=\dfrac{69.68464}{2\pi 0.55\times 10^3}\times 24\times 60\times 60\\\Rightarrow \dfrac{1}{T}=1742.24106\ rev/day

The rotation speed is 1742.24106 revolutions per day

6 0
3 years ago
Read 2 more answers
3. A wye-connected load has a voltage of 480 V applied to it. What is the voltage dropped across each phase?
ZanzabumX [31]

Answer:

E_s = 277.13V

Explanation:

Given

Load\ Voltage = 480V

Required

Determine the voltage dropped in each stage.

The relation between the load voltage and the voltage dropped in each stage is

E_l = E_s * \sqrt3

Where

E_l  = 480

So, we have:

480 = E_s * \sqrt3

Solve for E_s

E_s = \frac{480}{\sqrt3}

E_s = \frac{480}{1.73205080757}

E_s = 277.128129211

E_s = 277.13V

<em>Hence;</em>

<em>The voltage dropped at each phase is approximately 277.13V</em>

5 0
3 years ago
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