Answer:
730 items
Explanation:
The objective of the given information is to determine the number of hamburgers UAHH should order for the following conditions:
Average daily demand 600
Standard deviation of demand 100
Desired service probability 99%
Hamburger inventory 800
The formula for a given order quantity in a fixed period of time can be expressed as :

where;
= order quantity = ???
= daily demand average = 600
L = lead time in days = 1
T = time taken = 1
z = no of standard deviation = ???
= standard deviation of usage in lead time and time taken = ???
I = present inventory level = 800
=
× standard deviation of daily demand
= 
= 1.4142 * 100
= 141.42 items
From the Desired service probability 99% = 0.99; we can deduce the no of standard deviation by using the excel function (=NORMSINV (0.99))
z = 2.33
From 



q = 729.5086 items
q ≅ 730 items
Therefore; the number of hamburgers UAHH should order from the following given conditions = 730 items
Answer:
C, D , E , F.
Explanation:
These all are connected with money.
Sorry if I don't get this right I never had this question before.
Answer:
Land not currently used in operations - Long-term investments
Notes payable (due in five years) - Long-term liabilities
Accounts receivable - Current assets
Trademarks - Intangible assets
Accounts payable - Current liabilities
Store equipment - Plant assets
Wages payable - Current Liabilities
Cash - Current assets
Missing information attached along with the complete worksheet
Answer:
rent expense 1,700 debit
prepaid rent 1,700 credit
dep expense 350 debit
acc dep equip 350 credit
advertizing expense 1,400 debit
prepaid advertizing 1,400 credit
Explanation:
advertizing:
5,600 divide into 4 months = 1400 accrued per month
depreciaton:
42,000 / 10 years = 4,200
then we divide by 12 month: 350
Answer:
Depreciation for 6 months ending June 30, 2016 is $ 5,000 and the accounting entry to record the transaction is:
Depreciation Expense - Debit $ 5,000
Allowance for Depreciation - Credit $ 5,000
Explanation:
The depreciation charge for the year is calculated as follows:
Total cost of the equipment $ 55,000
Salvage Value $ 5,000
Net Depreciable value $ 50,000
Estimated Useful Life 5 years
Annual Depreciation expense(50000/5) $ 10,000
Depreciation for 6 months (10000/2) $ 5,000