<h3>
Answer:</h3>
2(CH3)2N2H2 + 3N2O4 → 4N2 + 4H2O + 4CO2 + heat
<h3>
Explanation:</h3>
- Balancing chemical equations involves putting coefficients on reactants and products.
- This results in an equal number of atoms of each element on either side of the equation.
- Balancing chemical equations ensures that the law of conservation of mass is obeyed.
- According to the law of conservation of mass, the mass of the reactants should be equal to the mass of products which is done by balancing chemical equations.
- Putting the coefficients, 2, 3, 4, 4, 4 on the equation makes the equation balanced.
- Therefore, the balanced equation would be;
2(CH3)2N2H2 + 3N2O4 → 4N2 + 4H2O + 4CO2 + heat
Answer:
Ok, so the process here is to convert the mass of H2 (hydrogen gas) to moles by dividing the mass by the molar mass of H2. Once you have the moles then you have to multiply by the STP (standard temperature and pressure) molar volume which should be 22.4.
Molar mass of H2 = (1.01)x2 = 2.02g/mol
19.3/2.02 = 9.55 moles
Now just multiply the moles by the molar volume
9.55 moles x 22.4 = 213.92 Litres of H2 are in 19.3g of H2
Heat
gained or loss in a system can be calculated by multiplying the given mass to the
specific heat capacity of the substance and the temperature difference. It is
expressed as follows:<span>
Heat = mC(T2-T1)
When two objects are in contact,
it should be that the heat lost is equal to what is gained by the other. So, the heat released by the lead is equal to the heat that is absorbed by the water.
</span>Heat = mC(T2-T1) = 50.0 mL (1.00 g/mL) (4.18 J/g °C) (20 °C - 18 °C) = 418 J<span>
</span>
Answer: Option (D) is the correct answer.
Explanation:
Vapor pressure is defined as the pressure exerted by the vapors which are present on the surface of a liquid.
For example, vapor pressure of water at room temperature is 0.0313 atm.
On the other hand, the temperature at which the vapor pressure of a liquid equals atmospheric pressure is known as boiling point.
For example, boiling point of water at room temperature is
.
Thus, we can conclude that vapor pressure can be described as the pressure exerted by a gas above the surface of its liquid.