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gayaneshka [121]
3 years ago
12

4. You are studying the behavior of a perfluorocarbon-based O2 carrier as an emergency treatment for hypoxemia. It has an approx

imate molecular radius of 2 nm. Consider ultrafiltration through the kidney (glomerular membrane pore radius 4 nm, length 800 nm). Assuming a therapeutic dose in the blood of 22 mM and 2 mM in the filtrate, determine the electrochemical potential across glomerular membrane.
Chemistry
1 answer:
Levart [38]3 years ago
7 0

Answer:

See explaination

Explanation:

The molecular radius of the perflurocarbon-based O2 carrier suggests that it passes through the Bowman’s capsule during ultrafiltration. Initial levels of the O2 carrier in blood are 22mM and concentration of the O2 carrier in the final glomerular filtrate is 2mM. Electrochemical potential is the driving source of energy required for the transport of a solute across the membrane. It is also known as the Gibbs free energy G. ΔG’o is the free energy change under standard conditions. Standard free energy change is directly related to the equilibrium constant (K’eq). Equilibrium is the state of the reaction where the concentration of the reactants equals the concentration of the products.

K’eq = [final concentration]/[initial concentration]

K’eq = 2mM/22mM = 0.09

ΔG’o = -RT ln K’eq ; R (gas constant) = 8.315 J/mol.K

T (temperature) = 298 K

ΔG’o = - (8.315 x 298) ln 0.09 = +5.96 kJ/mol

The separation of small molecules and ions from large molecules and cells in the blood is termed as ultrafiltration. The filtered out fluid is known as glomerular filtrate, capsular filtrate or ultrafiltrate. A nephron is a single unit of structure and function in a kidney.

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How many atoms of oxygen are present in 7.51 grams of<br> glycine with formula C₂H5O2N?
Blizzard [7]

1.205 × 10²³ atoms of oxygen will be present in 7.51 grams of glycine with formula C₂H5O2N. Details about number of atoms can be found below.

How to calculate number of atoms?

The number of atoms of a substance can be calculated by multiplying the number of moles of the substance by Avogadro's number.

However, the number of moles of oxygen in glycine can be calculated using the following expression:

Molar mass of C₂H5O2N = 75.07g/mol

Mass of oxygen in glycine = 32g/mol

Hence; 32/75.07 × 7.51 = 3.2grams of oxygen in glycine

Moles of oxygen = 3.2g ÷ 16g/mol = 0.2moles

Number of atoms of oxygen = 0.2 × 6.02 × 10²³ = 1.205 × 10²³ atoms

Therefore, 1.205 × 10²³ atoms of oxygen will be present in 7.51 grams of glycine with formula C₂H5O2N.

Learn more about number of atoms at: brainly.com/question/8834373

#SPJ1

3 0
2 years ago
Be sure to answer all parts.
Fudgin [204]

Answer:

2H₂ + O₂       →     2H₂O

Explanation:

Chemical equation:

H₂ + O₂       →     H₂O

Balance chemical equation:

2H₂ + O₂       →     2H₂O

Step 1:

H₂ + O₂       →     H₂O

Left hand side                     Right hand side

H = 2                                    H = 2

O = 2                                    O = 1

Step 2:

H₂ + O₂       →     2H₂O

Left hand side                     Right hand side

H = 2                                    H = 4

O = 2                                    O = 2

Step 3:

2H₂ + O₂       →     2H₂O

Left hand side                     Right hand side

H = 4                                    H = 4

O = 2                                    O = 2

7 0
3 years ago
Magnesium and bromine react to produce magnesium bromide. What is the balanced chemical equation for this reaction?​
tia_tia [17]

Answer:

MgBr2

Explanation:

On the periodic table, Magnesium has 2+ charge and Bromine has -1 charge.

You cross charges and get MgBr2

6 0
3 years ago
given two equations representing reactions: which type of reaction is represented by each of these equations?
Sergeeva-Olga [200]

Answer:

Equation 1 - nuclear fission

Equation 2 - nuclear fusion

Explanation:

Nuclear fission is a reaction in which a large nucleus is split into smaller nuclei when it is bombarded by neutrons. The process produces more neutrons to continue the chain reaction. This is clearly depicted in equation 1 as shown in the question.

Nuclear fusion is a reaction in which two light nuclei combine in order to form a larger nuclei. This is clearly depicted in equation 2 as shown in the question.

7 0
3 years ago
11C. Potassium hydrogen phthalate is a solid, monoprotic acid frequently used in the laboratory to standardize strong base solut
Llana [10]

For the reactants,

  • The oxidation number of hydrogen = +1
  • The oxidation number of oxygen = -2
  • The oxidation number of arsenic = +5
  • The oxidation number of carbon = +3

For the products,

  • The oxidation number of hydrogen = +1
  • The oxidation number of oxygen = -2
  • The oxidation number of arsenic = +3
  • The oxidation number of carbon = +4

Here, arsenic (+5 to +3) and carbon (+3 to +4) are the only oxidation numbers changing.

Note that an increase in oxidation number means electrons are lost. Thus oxidation is occurring, and a decrease in oxidation number means electrons are being gained, and thus reduction is occurring.

Also, the compound that contains the element being oxidized is the reducing agent, and the compound that contains the element being reduced is the oxidizing agent.

So, the answers are:

name of the element oxidized: Carbon

name of the element reduced: Arsenic

formula of the oxidizing agent: \text{H}_{3}\text{AsO}_{4}

formula of the reducing agent: \text{H}_{2}\text{C}_{2}\text{O}_{4}

6 0
2 years ago
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