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mixas84 [53]
3 years ago
9

Which of the following is not a part of Darwin’s theory of evolution?

Chemistry
2 answers:
OLEGan [10]3 years ago
7 0
A. Changes in organisms occur immediately.
Karo-lina-s [1.5K]3 years ago
4 0
A is the answer. Welcome
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When sugar glucose, C6H12O6, is burned with air, carbon dioxide and water vapor are produced. Write the balanced equation and ca
Alex Ar [27]
6CO2 + 6H2O YOU JUST ADD THEM TOGETHER
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3 years ago
Solid aluminum (AI) and oxygen (O_2) gas react to form solid aluminum oxide (Al_2O_3). Suppose you have 7.0 mol of Al and 9.0 mo
Nimfa-mama [501]

Answer:

There will be formed 3.5 moles of Al2O3 ( 356.9 grams)

Explanation:

Step 1: Data given

Numbers of Al = 7.0 mol

Numbers of mol O2 = O2

Molar mass of Al = 26.98 g/mol

Molar mass of O2 = 32 g/mol

Step 2: The balanced equation

4Al(s) + 3O2(g) → 2Al2O3(s)  

Step 3: Calculate limiting reactant

For 4 moles Al we need 3 moles O2 to produce 2 moles Al2O3

Al is the limiting reactant, it will be consumed completely (7 moles).

O2 is in excess.  There will react 3/4 * 7 = 5.25 moles

There will remain 9-5.25 = 3.75 moles

Step 4: Calculate moles Al2O3

For 4 moles Al we'll have 2moles Al2O3

For 7.0 moles of Al we'll have 3.5 moles of Al2O3 produced

Step 5: Calculate mass of Al2O3

Mass Al2O3 = moles Al2O3 * molar mass Al2O3

Mass Al2O3 = 3.5 moles* 101.96 g/mol

Mass Al2O3 = 356.9 grams

There will be formed 3.5 moles of Al2O3 ( 356.9 grams)

3 0
3 years ago
Someone please walk me through this. I googled way too much this semester and I'm paying for it on this test. Just tell me how t
alex41 [277]

Answer:

Explanation:

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4 0
3 years ago
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How much water should be added to 4.3 moles of LiBr to prepare a 2.05 m solution?
arsen [322]

Answer:

2.1 kg of water

Explanation:

Step 1: Given data

  • Moles of lithium bromide (solute): 4.3 moles
  • Molality of the solution (m): 2.05 m (2.05 mol/kg)
  • Mass of water (solvent): ?

Step 2: Calculate the mass of water required

Molality is equal to the moles of solute divided by the kilograms of solvent.

m = moles of solute/kilograms of solvent

kilograms of solvent = moles of solute/m

kilograms of solvent = 4.3 mol /(2.05 mol/kg) = 2.1 kg

8 0
2 years ago
Please help. balance this equation
Nuetrik [128]

Answer:

k=2

ci=2

o=6

k=2

ci=2

o=6

Explanation:

4 0
2 years ago
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