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MaRussiya [10]
1 year ago
6

Is gas occupies 733 cm at 10.9 at what temp will it occupy 950 cm

Chemistry
1 answer:
alexgriva [62]1 year ago
5 0

Temperature of gas at volume of 950 cm³ is 368.14K or 94.99⁰c.

  • Volume is the amount of space a three-dimensional object takes up, expressed in cubic units.
  • units of volume are mL, liter, cm³ or m³.

Given,

in this question, volume occupied by gas at 10.9⁰c is 733cm³.

we have to find out temperature at which gas occupies volume of 950 cm³.

First, convert temperature from celcius to Kelvin

10.9⁰c = 10.9 + 273.15 = 284.05 K

By equation or Boyle's Law

P1 x V1 / T1 = P2 x V2 / T2

Pressure is constant here

therefore, V1 / T1 = V2 / T2

here, V1 = 733 cm³

T1 = 284.05 K

V2 = 950 cm³

we have to find out T2

So, 733 / 284.05 = 950 / T2

T2 = 284.05 × 950 / 733 = 368.14 K

= 94. 99⁰c

Therefore the temperature of gas at volume of 950 cm³ is 368.14K or 94.99⁰c.

Learn more about Boyle's Law here:

https://brainly.in/question/2900894

#SPJ9

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3 years ago
Write the net ionic equation for the acid-base hydrolysis equilibrium that is established when ammonium perchlorate is dissolved
Whitepunk [10]

<u>Answer:</u> The net ionic equation is written below.

<u>Explanation:</u>

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are defined as the ions which do not get involved in the chemical equation. It is also defined as the ions which are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of ammonium perchlorate and water is given as:

NH_4ClO_4(aq.)+H_2O(l)\rightarrow NH_4OH(aq.)+HClO_4(aq.)

Ionic form of the above equation follows:

NH_4^+(aq.)+ClO_4^-(aq.)+H_2O(l)\rightarrow NH_4OH(aq.)+H^+(aq.)+ClO_4^-(aq.)

Ammonium hydroxide will not dissociate into its ions because it is a weak base.

As, chlorate ions are present on both the sides of the reaction, thus, it will not be present in the net ionic equation.

The net ionic equation for the above reaction follows:

NH_4^+(aq.)+H_2O(l)\rightarrow NH_3^+(aq.)+H_3O^+(aq.)

Hence, the net ionic equation is given above.

5 0
3 years ago
Based on the following molecular weight data of polypropylene, determine the degree of polymerization Molecular Weight Range (g/
Lady bird [3.3K]

Answer:

785

Explanation:

Molecular. X. W

Weight

8000-16000 0.05 0.03

16000-24000. 0.017. 0.08

24000-32000. 0.22. 0.18

32000-40000. 0.25. 0.35

40000-48000. 0.22. 0.27

48000-56000. 0.09. 0.09

Mean weight X*M. W*M

12000. 600. 240

20000. 3200. 2000

28000. 6720. 5600

36000. 10080. 10800

44000. 8800. 11880

52000. 3640 3640

Total=33040g\mol 36240

Note before repeat molecular weight m= 3*12.01+6*1.008=

42.08g/mol

Degree of polymerization= total W*M/w=33040/42.08 =785

8 0
3 years ago
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