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nadya68 [22]
2 years ago
10

The first ionization energy of an element is the energy required to remove an electron from a gaseous atom of an element to prod

uce a +1 ion:
M(g) + energy ---> M ^(+) (g) + e -
How do you think the activity of an element ought to be related to its first ionization energy? Predict a decreasing order of reactivity of the above elements based on their first ionization energies.
Chemistry
1 answer:
skad [1K]2 years ago
8 0

Answer:

The higher the ionization energy, the lower the reactivity.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to draw a conclusion about the relationship between ionization energy and reactivity, by bearing to mind that the former is the energy the atom needs to lose its electron, this means that the higher the energy, the more difficult is for the atom to do so.

Based on the aforementioned, since the reactivity is related to how likely an atom undergoes a chemical change by losing or gaining electrons, we can say that the reactivity decreases as the ionization energy increase as, again, it is more difficult for the atom to have an excited state allowing its chemical interaction with another substance.

Unfortunately, the "above elements" where not given, so this part could not be solved, however, you can use the attached periodic trend for ionization energy to figure out the correct order, by keeping in mind the previous reasoning.

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What is the Nobel gas notation for selenium​
seraphim [82]

Answer:

Se =[Ar] 3d¹⁰ 4s² 4p⁴

Explanation:

The noble gas notation is used for the shortest electronic configuration of other periodic table elements.

For example:

The atomic number of Argon is 18, and its electronic configuration is,

Ar₁₈ = 1s² 2s² 2p⁶ 3s² 3p⁶

The atomic number of selenium is 34, its electronic configuration is,

Se₃₄ = 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p⁴

By using the noble gas notation, electronic configuration of selenium can be written is shortest form.

Se =[Ar] 3d¹⁰ 4s² 4p⁴

This electronic configuration is also called abbreviated electronic configuration.

5 0
3 years ago
a. For the reaction 2H2 + 02→ 2H20, how many moles of water can be produced from 6.0 mol of oxygen? 2.0 mol b. 6.0 mol 12 mol d.
pickupchik [31]

Explanation:

from the equation 1 mole of O2 will give 2 moles of H2O then 6.0 moles of O2 will give x

6.0*2 moles/ 1 mole

= 12 moles

this implies that, 6.0 moles of O2 will give = 12 moles of water

3 0
2 years ago
What is a total ionic equation ?!
vodomira [7]
An ionic equation contains two ions in the full equation
5 0
3 years ago
A solution contains 2 meq/ml of kcl. if a 20 ml ampule of this solution is diluted to 1 liter what is the percent strength of th
Serjik [45]

We are given that the concentration of the KCl is 2 meq / mL. Assuming that the ampule also has exactly this concentration, therefore:

 

amount of KCl in ampule = (2 meq / mL) * (20 mL)

amount of KCl in ampule = 40 meq

 

This amount of KCl is now inside a solution of 1 Liter (also equivalent to 1000 mL), therefore the new concentration in the resulting solution is:

new concentration = 40 meq / 1000 mL

new concentration = 0.04 meq / mL

 

Since 0.04 in decimal is 4% in percentage, therefore the strength of the resulting solution is 4% KCl.

7 0
3 years ago
Dissolve 7, 8 grams of Mg and Al mixture with excess HCl solution. After the reaction, the mass of acid solution increased by 7,
fgiga [73]

Answer:

Mg = 2,5 g; Al = 5,3 g  

Explanation:

1) Reactions

Mg + 2HCl ⟶ MgCl₂ +   H₂

2Al + 6HCl ⟶ 2AlCl₃ + 3H₂

2) Mass of each metal

If there had been no reaction, the mass of the solution would have increased by 7,8 g.

The mass increased by only 7,0 g.

The missing 0,8 g must represent the mass of the hydrogen generated by the reaction.

We have two relations:

Mass of Mg + mass of Al = 7,8 g

H₂ from Mg + H₂ from Al = 0,8 g

i) Calculate the moles of H₂

n = \text{0,8 g H}_{2} \times \dfrac{\text{1 mol H}_{2}}{\text{2,016 g H}_{2}} = \text{0.40 mol H}_{2}

(ii) Solve the relationship

  Let x = mass of Mg. Then

7,8 - x = mass of Al

Moles of Mg = x/24.30

Moles of Al = (7,8 - x)/26.98

Moles of H₂ from Mg = (1/1) × moles of Mg = 1 × (x/24,30) = 0,0412x

Moles of H₂ from Al = (3/2) × Moles of Al = 1.5(7,8 - x)/26,98 = (11,7 -1,5x)/26,98

\begin{array}{rcl}0,0412x + \dfrac{ 11,7 - 1,5x }{26,98} &= &0,40\\\\ 1,11x + 11.7 - 1,5x &=& 10.7\\-0.39x& = &-1.0\\x &=& \text{2.5 g}\\\end{array}

Mass of Mg = 2,5 g

Mass of Al = 7,8 g - 2,5 g = 5,3 g

The masses of the metals are Mg = 2,5 g; Al = 5,3 g

6 0
3 years ago
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