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3 years ago

How are seeds different from spores?

Physics

1 answer:

andrew11 [14]3 years ago

3 0

Explanation:

1.<u>Seeds have endosperm which provides nourishment for a new plant, but spores do not have any stored food supplies.</u>

hope it helpful

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Does a light switch have electrical potential energy or mechanical energy

nordsb [41]

Turning on a light switch converts mechanical energy to electrical and radiant energy. So Mechanical energy

7 0

4 years ago

Read 2 more answers

The Chevy Corvette Z06 is claimed to accelerate from a standing start to 60 miles per hour in 3 seconds. Estimate its accelerati

Vika [28.1K]

Answer:

The acceleration of Chevy Corvette is $8.94\ m/s^2$ .

Explanation:

Given that,

Initial speed of Chevy Corvette Z06, u = 0 (it starts from rest)

Final speed of Chevy Corvette Z06, v = 60 mph

1 mph = 0.44704 m/s

60 mph = 26.82 m/s

Time, t = 3 seconds

We need to find the acceleration of Chevy Corvette. The rate of change of velocity is called acceleration of an object. It is given by :

$a=\dfrac{v-u}{t}$

$a=\dfrac{v}{t}$

$a=\dfrac{26.82\ m/s}{3\ s}$

$a=8.94\ m/s^2$

So, the acceleration of Chevy Corvette is $8.94\ m/s^2$ . Hence, this is the required solution.

4 0

4 years ago

Consider a rifle, which has a mass of 2.44 kg and a bullet which has a mass of 150 grams and is loaded in the firing chamber.Whe

svetlana [45]

Answer:

a. 0 kgm/s

b. 0 kgm/s

c. 66 kgm/s

d. -66 kgm/s

e. 0 kgm/s

f. -27.05 m/s

g. 173.68 N

h. 12.58 m/s

i. 0.772 m

j. 14487 J

Explanation:

150 g = 0.15 kg

a. Before the bullet is fired, both rifle and the bullet has no motion. Therefore, their velocity are 0, and so are their momentum.

b. The combination is also 0 here since the bullet and the rifle have no velocity before firing.

c. After the bullet is fired, the momentum is:

0.15*440 = 66 kgm/s

d. As there's no external force, momentum should be conserved. That means the total momentum of both the bullet and the rifle is 0 after firing. That means the momentum of the rifle is equal and opposite of the bullet, which is -66kgm/s

e. 0 according to law of momentum conservation.

f. Velocity of the rifle is its momentum divided by mass

v = -66 / 2.44 = -27.05 m/s

g. The average force would be the momentum divided by the time

f = -66 / 0.38 = 173.68 N

h. According the momentum conservation the bullet-block system would have the same momentum as before, which is 66kgm/s. As the total mass of the bullet-block is 5.1 + 0.15 = 5.25. The velocity of the combination right after the impact is

66 / 5.25 = 12.58 m/s

i. The normal force and also friction force due to sliding is

$F_f = N\mu = Mg\mu = 5.25*9.81*0.83 = 42.75N$