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Alex787 [66]
3 years ago
6

Some planetary scientists have suggested that the planet Mars has an electric field somewhat similar to that of the earth, produ

cing a net electric flux of 3.67×1016 N⋅m2/C⋅ into the planet's surface.Calculate: (a) the total electric charge on the planet; (b) the electric field at the planet’s surface (refer to the astronomical data inside the back cover); (c) the charge density on Mars, assuming all the charge is uniformly distributed over the planet’s surface.
Physics
1 answer:
aalyn [17]3 years ago
6 0

Answer:

324795 C

252.637820565 N/C

2.235844712\times 10^{-9}\ C/m^2

Explanation:

\epsilon_0 = Permittivity of free space = 8.85\times 10^{-12}\ F/m

R = Radius of Mars = 3.4\times 10^6\ m

A = Area = 4\pi R^2

\phi = Electric flux = 3.67\times 10^{16}\ Nm^2/C

Electric flux is given by

\phi=\dfrac{q}{\epsilon_0}\\\Rightarrow q=\phi\epsilon_0\\\Rightarrow q=3.67\times 10^{16}\times 8.85\times 10^{-12}\\\Rightarrow q=324795\ C

The charge is 324795 C

Electric field is given by

E=\dfrac{\phi}{A}\\\Rightarrow E=\dfrac{3.67\times 10^{16}}{4\pi (3.4\times 10^6)^2}\\\Rightarrow E=252.637820565\ N/C

The electric field is 252.637820565 N/C

Surface charge density is given by

\sigma=\dfrac{q}{4\pi R^2}\\\Rightarrow \sigma=\dfrac{324795}{4\pi (3.4\times 10^6)^2}\\\Rightarrow \sigma=2.235844712\times 10^{-9}\ C/m^2

The surface charge density is 2.235844712\times 10^{-9}\ C/m^2

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