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The total energy TE = mgh + 1/2 mU^2; where h = 20 m, g = 9.81 m/sec^2, and U = 10 mps. When the ball reaches max height H, all that TE will be potential energy PE = mgH = TE.
So there you are. TE = mgh + 1/2 mU^2 = mgH = TE from the conservation of energy. Solve for H.
1) H = (gh + 1/2 U^2)/g = h + U^2/2g = ? meters where everything on the RHS is given. You can do the math.
2) As the ball drops from H to h, it picks up KE as the potential energy mgH is converted when the potential energy is diminished to mgh, where h < H. So PE - pe = ke = mg(H - h) = 1/2 mv^2 so solve for v = sqrt(2g(H - h)) and, again, everything is given. You can do the math.
3) Same deal as 2) except now its V = sqrt(2gH) because all the PE = mgH = 1/2 mV^2 = KE when it is about to hit the ground. You can do the math.
Answer:
Explanation:
- The concept of gibb's free energy is applied in the problem. Mathematically from Gibb's free energy ; ΔG = ΔH - TΔS
- Entropy = ΔS = is the degree of disorderliness of the system.
- Since the enthalpy of vaporization is given ΔHvap = 38.0kJ/mol = 38000J/mol
- Also ΔSvap = 112.9J/mol.K
- Temperature of the experiment given = 75 degree celsius
calculate the boiling point of the solvent ; T = ΔHvap/ΔSvap
- T = 38000J/mol / 112.9J/mol.K
- = 335.57K , in celsius ; 335.57K - 273
the temperature calculated indicates that the solvent is not suitable for the experiment because its boiling point is lesser than the temperature at which the experiment want to be carried out.
We know
Pa=Patm+dgh+dgl
here Pa is pressure in pipe with higher level of liquid
Patm is atmospheric pressure
d is density
g is gravitational constant
h is height of lower liquid
l is difference is height of higher liquid
So Pb= Patm+dgh
here Pb is pressure lower level pipe
so
Pdiff=Pb-Pa
Pdiff=-dgl
We know
Density of kerosene is the reciprocal of it’s specific volume
so d=1/v=1/0.00122=820kg/m3
as g=9.81 and l=12cm
Pdiff= - 820*9.81*12/100
Pdiff = -965.304 Pa
Negative sign shows pressure decreases as the kerosene flows from point A
to point B as the pipe diameter decreases.
From the freezing temperature up to about 4°C (39°F) the water CONTRACTS. That is, it becomes MORE dense. I think I read that water is the ONLY known substance whose solid phase floats in its liquid phase. That's why the cubes float in your soda and bergs float in the ocean. And if weren't so, then life on Earth would not be possible ! Oceans and lakes would freeze from the bottom up, ONE TIME, and then never thaw again.
Well in rollercoasts u have low points and high points. at the high points you have potential energy and at the low points you have kinetic energy, but the energy remains equal throughout.