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iogann1982 [59]
3 years ago
14

If it takes 150 N of force to move a box. 10 meters, what is the work done on

Physics
1 answer:
Scrat [10]3 years ago
3 0

Answer:

C ) 1500 Joules

Explanation:

In the attached image, we can see how the box was moved 10 meters by the force of 150 N.

The definition of work is W = F * d

therefore

W= 150*10 = 1500 J

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Draw velocity-ime graph for uniform moion of an object , when initially body is at rest.
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It's impossible to tell, based on the given information, how these two parts of the
graph are connected.  There must be some sloping (accelerated) portion of the graph
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8 0
3 years ago
A small sphere is at rest at the top of a frictionless semicylindrical surface. The sphere is given a slight nudge to the right
V125BC [204]

Answer:

vi = 4.77 ft/s

Explanation:

Given:

- The radius of the surface R = 1.45 ft

- The Angle at which the the sphere leaves

- Initial velocity vi

- Final velocity vf

Find:

Determine the sphere's initial speed.

Solution:

- Newton's second law of motion in centripetal direction is given as:

                         m*g*cos(θ) - N = m*v^2 / R

Where, m: mass of sphere

             g: Gravitational Acceleration

             θ: Angle with the vertical

             N: Normal contact force.

- The sphere leaves surface at θ = 34°. The Normal contact is N = 0. Then we have:

                         m*g*cos(θ) - 0 = m*vf^2 / R

                         g*cos(θ) = vf^2 / R    

                         vf^2 = R*g*cos(θ)

                         vf^2 = 1.45*32.2*cos(34)

                        vf^2 = 38.708 ft/s

- Using conservation of energy for initial release point and point where sphere leaves cylinder:

                          ΔK.E = ΔP.E

                          0.5*m* ( vf^2 - vi^2 ) = m*g*(R - R*cos(θ))

                          ( vf^2 - vi^2 ) = 2*g*R*( 1 - cos(θ))

                          vi^2 =  vf^2 - 2*g*R*( 1 - cos(θ))

                          vi^2 = 38.708 - 2*32.2*1.45*(1-cos(34))

                          vi^2 = 22.744

                           vi = 4.77 ft/s

4 0
3 years ago
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alexgriva [62]
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3 0
3 years ago
Please need help on this not too sure on this
n200080 [17]

Answer:

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Explanation:

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3 0
3 years ago
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Answer:

ΔE = 9.7mJ

Explanation:

See attachment below.

7 0
3 years ago
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