Answer:
Use the method on the image and solve it.
Answer:
Showing results for Two point charge q, separated by 1.5cm have change value of +2.0 and -4.0AND/C respectively what is the magnitude of the Electric force midway between them?
Search instead for Two point charge q, seperated by 1.5cm have change value of +2.0 and -4.0N/C respectively what is the magnitude of the Electric force midway between them?
initial velocity of the car given as
![v_i = 0](https://tex.z-dn.net/?f=v_i%20%3D%200)
final velocity is given as
![v_f = 108 km/h](https://tex.z-dn.net/?f=v_f%20%3D%20108%20km%2Fh)
as we know that
![1 km/h = 0.277 m/s](https://tex.z-dn.net/?f=1%20km%2Fh%20%3D%200.277%20m%2Fs)
now we can convert final speed into m/s
![v_f = 108 * 0.277 = 30 m/s](https://tex.z-dn.net/?f=v_f%20%3D%20108%20%2A%200.277%20%3D%2030%20m%2Fs)
now acceleration is rate of change in velocity
![a = \frac{v_f - v_i}{t}](https://tex.z-dn.net/?f=a%20%3D%20%5Cfrac%7Bv_f%20-%20v_i%7D%7Bt%7D)
![a = \frac{30 - 0}{10}](https://tex.z-dn.net/?f=a%20%3D%20%5Cfrac%7B30%20-%200%7D%7B10%7D)
![a = 3 m/s^2](https://tex.z-dn.net/?f=a%20%3D%203%20m%2Fs%5E2)
so the acceleration of the car is 3 m/s^2
Answer:
B) x^2+6x+8
Explanation:
x-4 | x^3+2x^2-16x-32
- x^3-4x^2 <-- (x-4)(x^2)
_________________
6x^2-16x-32
- 6x^2-24x <-- (x-4)(6x)
_________________
8x-32
- 8x-32 <- (x-4)(8)
___________________________
0 | x^2+6x+8
This means the answer is B) x^2+6x+8