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OLga [1]
4 years ago
15

the impact time for a particular collision is 3.0 × 10-3 seconds and the impulse in the collision is 0.30 newton seconds. what i

s the force of the collision?
Physics
1 answer:
Zanzabum4 years ago
3 0
There are several information's already given in the question. The answer can be easily deduced using those information's. 

Time = 3.0 * 10-3 seconds
Impulse = 0.30 newton
Then
Force = Impulse/Time
          = 0.30/3.0 * 10-3
          = 1 * 10^3 newtons.
I hope the above procedure is clear for you to understand and it has actually come to your great help.
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An infinite slab of charge of thickness 2z0 lies in the xy-plane between z=−z0 and z=+z0. The volume charge density rho(C/m3) is
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Explanation:

To find the electric field you can consider the Gaussian law for a cylindrical surface inside the slab.

\int E dA=EA_{G}=\frac{Q_{int}}{\epsilon_o}

Q_{int}=\rho V_{G}

where Qint is the charge inside the Gaussian surface, AG is the area of the surface and rho is the charge density of the slab.

By using the formula for the volume of a cylinder you obtain:

V_{G}=\pi r^2h

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E=\frac{Q_{int}}{\epsilon_o A_G}=\frac{Q_{int}}{\epsilon_o \pi r^2}\frac{z}{z}=\frac{\rho z}{\epsilon_o}

E=\rho z/\epsilon_o

hence, for z>0 you obtain E=pz/eo > 0

for z<0 -> E=pz/eo < 0

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