Ask question

Ask question

All categories

3 years ago

12

Ok, so this question is probably really easy but I can't really be bothered to answer it, terrible I know, but I thank all usefu

l answers

1 answer:

Dvinal [7]3 years ago

3 0

Without a bulb energy cant go through and it would be an open circuit blocking the energy from coming out.

You might be interested in

What’s the answer to 12

Schach [20]

Speed is v = d/t

Or speed is distance over time

So...

40min / 60min = 0.6667 or 2/3 --> Finding what proportion 40 minutes is to an hour or 60 minutes as we need the units of hours to match up

45km/h = d/0.6667h

d = (45)(0.667)

d = 30.0015 or 30km

4 0

3 years ago

Read 2 more answers

Which of the following correctly arranges the planets by the size of their diameter in increasing order?

valentinak56 [21]

Increasing Order..
So, it's from the little one into the biggest one..

My Answer is
C: Mercury < Earth < Saturn < Jupiter

What Shape of The Earth ?
Is it Round or Flat ?
Subjective Answer..

7 0

3 years ago

Read 2 more answers

Which best summarizes the scientific process that led to our current understanding of DNA? Please help

solniwko [45]

The answer is B.)

This is because for years scientists have build up and found discoveries that led to recent discoveries brought by previous scientists.

Hope this helps

7 0

3 years ago

Read 2 more answers

dybincka [34]

Answer:

1. 218.55 N

2. $30.96^{o}$

3. $2.1 m/s^{2}$

Explanation:

Part 1;

Net force $F=mg sin \theta$ where m is mass, g is gravitational force and $\theta$ is the angle of inclination

$F= 46*9.8*sin 29^{o}= 218.55N$

Frictional force, $F_{r}$ is given by

$F_{r} = \mu_{s}mg cos \theta$ where $\mu_{s}$ is the coefficient of static friction

$F_{r} = 0.6*46*9.8 cos 29$

$F_{r}=236.57N$

Since $F_{r}>F$ , therefore, the block doesn’t slip and the frictional force acting is mgh=218.55N

Part 2.

Using the relationship that

Frictional force $F_{s} = \mu_{s} mg cos \theta$

$mg sin \theta =\mu_{s} mg cos \theta$

$\mu_{s}= \frac {sin \theta}{cos \theta}$

$\mu_{s}= tan \theta$

The maximum angle of inclination $\theta = tan^{-1} \mu_{s}$

$\theta = tan^{-1} (0.6)$

$\theta= 30.96^{o}$

Part 3:

Net force on the object is given by

$ma = mg sin 38 - \mu_{k} mg cos 38$ where $\mu_{k}$ is the coefficient of kinetic friction

$a = g ( sin 38 - \mu_{k} cos 38 )$

= 9.8 ( sin 38 - (0.51) cos 38 )

= $2.1m/s^{2}$

7 0

3 years ago

The children asked about the electric train and how to use it.

juin [17]

U use the train to play hope i helped please thank me

3 0

3 years ago