Answer:
Elements are pure substances which are composed of only one type of atom. Compound are substances which are formed by two or more different types of elements that are united chemically in fixed proportions. ... Some of the examples of elements are Iron, Copper, Gold, etc. A few examples of compounds are NaOH, NaCl, etc.
Answer:
u will equate and make V2 the subject because it's the one u are looking for ....
Moles of PF₃ : 4
<h3>Further explanation</h3>
A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.
Reaction
![\tt P_4(s)+6F_2(g)\rightarrow 4PF_3(g)](https://tex.z-dn.net/?f=%5Ctt%20P_4%28s%29%2B6F_2%28g%29%5Crightarrow%204PF_3%28g%29)
1.25 moles of P₄(s) is reacted with 6 moles of F₂(g)
Limiting reactant : the smallest ratio (mol divide by coefficient)
P₄ : F₂ =
![\tt \dfrac{1.25}{1}\div \dfrac{6}{6}=1.25\div 1\rightarrow F_2~limiting~reactant(smallest~ratio)](https://tex.z-dn.net/?f=%5Ctt%20%5Cdfrac%7B1.25%7D%7B1%7D%5Cdiv%20%5Cdfrac%7B6%7D%7B6%7D%3D1.25%5Cdiv%201%5Crightarrow%20F_2~limiting~reactant%28smallest~ratio%29)
mol PF₃ based on mol of limiting reactant(F₂), so mol PF₃ :
![\tt \dfrac{4}{6}\times 6~moles=4~moles](https://tex.z-dn.net/?f=%5Ctt%20%5Cdfrac%7B4%7D%7B6%7D%5Ctimes%206~moles%3D4~moles)
ANSWERS:
1.
![2KClO_{3}](https://tex.z-dn.net/?f=2KClO_%7B3%7D%20%20)
⇒ 2KCl +
![3O_{2}](https://tex.z-dn.net/?f=3O_%7B2%7D%20)
2.
![H_{2} C_{2} O_{4} + 2NaOH](https://tex.z-dn.net/?f=%20H_%7B2%7D%20%20C_%7B2%7D%20O_%7B4%7D%20%20%2B%202NaOH%20%20)
⇒
![Na_{2} C_{2} O_{4} + 2 H_{2} O](https://tex.z-dn.net/?f=%20Na_%7B2%7D%20%20C_%7B2%7D%20O_%7B4%7D%20%20%2B%202%20H_%7B2%7D%20O)
3.
![2 C_{10} H_{22} + 31O_{2}](https://tex.z-dn.net/?f=2%20C_%7B10%7D%20%20H_%7B22%7D%20%2B%20%2031O_%7B2%7D%20%20)
⇒
![20C O_{2} + 22 H_{2} O](https://tex.z-dn.net/?f=20C%20O_%7B2%7D%20%2B%2022%20H_%7B2%7D%20O)
4.
![4 H_{2} + Fe_{3} O_{4}](https://tex.z-dn.net/?f=4%20H_%7B2%7D%20%2B%20Fe_%7B3%7D%20O_%7B4%7D%20)
⇒
![3Fe +4 H_{2} O](https://tex.z-dn.net/?f=3Fe%20%2B4%20H_%7B2%7D%20O)
5.
![4P + 5 O_{2}](https://tex.z-dn.net/?f=4P%20%2B%205%20O_%7B2%7D)
⇒
![2 P_{2} O_{5}](https://tex.z-dn.net/?f=2%20P_%7B2%7D%20%20O_%7B5%7D%20)
I have attached my work for 1-3. I would like to see if you can get 4 and 5 on your own. but, if you are struggling/copnfused please let me know in the comments! :)