Answer:
The electron configuration for Iron (Fe) with 26 electrons is as follows 1s²2s²2p⁶3s²3p⁶4s²3d⁶ (the superscripts add up to 26) or the Noble gas [Ar] 4s²3d⁶
Explanation:
The subshells fill up in the order 1s, 2s,2p, 3s,3p,4s,3d... (etc) the subshells have the following number of e⁻ (electrons) s: 2, p:6, d:10, f:14. I attached the subshell levels and where to find them on the periodic table that I made when I taught this to myself after lecture. You can use the noble gas from the previous row to make this simpler to write.
Answer:
your answer is hawks
THE RADIUS OF THE TENTH ORBIT IN A HYDROGEN ATOM IS 52.9A°
<h3>How does an electron orbit work? </h3>
The three-dimensional area covering the nucleus of an atom is called electron orbital. Electrons sometimes fill low-energy orbitals which are closer to the nucleus before filling the higher ones. They mostly fill the orbitals as singly as they can and that filling is known as Hund’s rule. In the wave-like property, electrons don’t orbit a nucleus in the way a planet orbits the sun but however, but they exist as standing waves. The lowest energy possible an electron can take is the same as the fundamental frequency of a wave on a string.
the radius of the first orbit =0.0529nm
radius ∝ n²/z
radius of 10th orbit =(0.0529×100)nm=52.9A°
To learn more about Electron orbit,visit:
brainly.com/question/19132667
#SPJ4
Answer:
The calculations is shown in the attached file.
Explanation:
- The concept of dipole moment is applied here. the size of the dipole moment is given by multiplying the size of the charge by the distance apart.
- For simpler molecules, the sizes of the dipole moments are approximately proportional to the difference between the electronegativities of the atoms. Dipole moments are usually measured in debyes (D).
Dipole moments (μ) = q x r
The detailed calculation is shown in the attachment.