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Ket [755]
3 years ago
5

A neutral atom in the ground state of Sulfur has its outer most valence electron in which orbital? f d

Chemistry
1 answer:
Natasha_Volkova [10]3 years ago
3 0

<u>Answer:</u> The outermost valence electron enters the p orbital.

<u>Explanation:</u>

Valence electrons are defined as the electrons which are present in outer most orbital of an atom.

Sulfur is the 16th element of the periodic table having 16 electrons.

Electronic configuration of sulfur atom is 1s^22s^22p^63s^23p^4

The number of valence electrons are 2 + 4 = 6

These 6 electrons enter s-orbital and p-orbital but the outermost valence electron will enter the p-orbital.

Hence, the outermost valence electron enters p orbital.

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Dan described two layers of Earth's atmosphere.
saul85 [17]

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b)stratosphere: next to troposhere

c)mesosphere:above stratosphere, here lowest temperature is observed

d)Thermosphere and Ionosphere: This layer allows long distance radio communication

e)Exosphere: this layer separates outer space from earth's surface.

4 0
2 years ago
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A bluebird lives in a maple tree. It builds a nest in the tree, where its eggs can be protected from the harsh environment. This
zysi [14]

Answer:

commensalism

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Explanation:

if the bird only nest in it and

the tree isn't really bothered or affected by the bird.

4 0
2 years ago
Which of the following best defines velocity?
Lina20 [59]

Answer: D

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Because velocity is speed

8 0
3 years ago
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What volume (in milliliters) of oxygen gas is required to react with 4.03 g of Mg at STP?
BigorU [14]
Mg reaction with O₂ gas will produce MgO so the equation will be
2Mg+O₂⇒2MgO. (You have to find the equation in order two figure out the number of moles of O₂ that will react with 1 mole of MgO).

The first step is to find the number of moles of Mg in 4.03g of Mg.  You can do this by dividing 4.03g Mg by its molar mass (which is 24.3g/mol) to get 0.1658mol Mg.  Then you have to find the number of moles of O₂ that will react with 0.1658mol Mg.  To do this you need to use the fact that 1mol O₂ will react with 2mol Mg (this reatio is from the chemical equation) so you have to multiply 0.1658mol Mg by (1mol O₂)/(2mol Mg) to get 0.0829mol O₂.  From here you would usually use PV=nRT and solve for V However, the question tells us that we are at STP, that means you can use the fact that 22.4L of gas is 1 mol of gas at STP.  Using that information we can find the volume of O₂ gas by mulitlying 0.0829mol O₂ by 22.4L/mol to get 1.857L which equals 1857mL.
therefore, 1857mL of O₂ gas will react with 4.03g of Mg.

I hope this helps. Let me know in the comments if anything is unclear.
6 0
3 years ago
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Fill in the coefficients to balance the equation for the chemical reaction that occurs:
Dominik [7]

Answer:

The equation is balanced

Explanation:

NaCl (aq) + AgNO3(aq) ––> AgCl (s) + NaNO3 (aq)

NaCl (aq) + AgNO3 (aq)

Na = 1 , Cl=1 , Ag = 1 , No3= 1

AgCl (s) + NaNO3 (aq)

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8 0
2 years ago
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