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3 years ago

A neutral atom in the ground state of Sulfur has its outer most valence electron in which orbital? f d

Chemistry

1 answer:

Natasha_Volkova [10]3 years ago

3 0

<u>Answer:</u> The outermost valence electron enters the p orbital.

<u>Explanation:</u>

Valence electrons are defined as the electrons which are present in outer most orbital of an atom.

Sulfur is the 16th element of the periodic table having 16 electrons.

Electronic configuration of sulfur atom is $1s^22s^22p^63s^23p^4$

The number of valence electrons are 2 + 4 = 6

These 6 electrons enter s-orbital and p-orbital but the outermost valence electron will enter the p-orbital.

Hence, the outermost valence electron enters p orbital.

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Which statement justifies that phosphine (PH3) is a polar molecule?

lorasvet [3.4K]

The P-H bond is polar and the molecule is asymmetric.

Non-polar bonds cannot produce polar molecules and symmetric bonds result in even distribution of charge, so no net charge is observed.

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3 years ago

Sodium chloride (NaCl) is commonly used to melt ice on roads during the winter. Calcium chloride (CaCl2) is sometimes used for t

mihalych1998 [28]

Answer:

$\Delta Tfp_{NaCl}= -14.0\°C\\\\\Delta Tfp_{CaCl_2}=-11.1\°C$

Explanation:

Hello!

In this case, since the freezing point depression caused by the addition of a solute, we use the following formula:

$\Delta Tfp= i*m*Kfp$

Thus, we first need to compute the molality of each solute, as shown below:

$m_{NaCl}=\frac{220.g/(58.44g/mol)}{1.00kg} =3.76m\\\\m_{CaCl_2}=\frac{220.g/(110.98g/mol)}{1.00kg} =1.98m$

Next, since NaCl has two ionic species, one Na⁺ and one Cl⁻, and CaCl₂ three, one Ca²⁺ and two Cl⁻, the van't Hoff's factors are 2 and 3 respectively, therefore the freezing point depressions turn out:

$\Delta Tfp_{NaCl}= 2*3.76m*-1.86\°C/m=-14.0\°C\\\\\Delta Tfp_{CaCl_2}= 3*1.98m*-1.86\°C/m=-11.1\°C$

It means that CaCl₂ is still better than NaCl because produces involves a higher melting point for the ice, so it would melt faster.

Best regards!

3 0

2 years ago

How many grams of chlorine gas must react to give 3.52g of BiCl3 according to the equation in exercise 23?

marshall27 [118]

3.52g BiCl3 × 1 mol BiCl3/ 315.34g BiCl3 × 3 mol Cl/ 2 mol BiCl3 × 70.906g Cl/ 1 mol Cl= 1.187 g Cl

6 0

3 years ago

Read 2 more answers

If heat is supplied to the stillpot too rapidly, the ability to separate two liquids by fractional distillation may be drastical

hram777 [196]

Answer: The boiling points of the two liquids are quickly exceeded

Explanation:

Fractional distillation is a method of separating a mixture of liquids where each has different boiling points.

To therefore obtain individual fractions, temperature rise of the mixture must be gradual, otherwise the boiling points of the two liquids will be quickly exceeded making collection of each fraction impossible.

4 0

3 years ago

B) calculate the ratio of moles of h2o to moles of anhydrous kal(so4)2. note: report the ratio to the closest whole number. (sho

Sindrei [870]

Answer: -

Mass of Hydrated KAl(SO₄)₂ = 2.0 g

Molar mass of anhydrous KAl(SO₄)₂ = 258.20 g/ mol

Mass of of anhydrous KAl(SO₄)₂ = mass of the 2nd heating = A

The mass of water released = mass of the Aluminum Cup + 2.0 grams of KAl(SO₄)₂ - mass of the 2nd heating

= H g

Moles of water released = $\frac{H g}{18 g/mol}$