You have to provide options, otherwise people will not reply to your question.
For us to accurately determine what compound
this is, additional info must be given. However I can suggest two compounds
which have molecular mass of about 30.07 g/mol.
1. It could be NO or nitric oxide.
The molecular mass is 16 + 14= 30 g/mol
But if we search the exact weight, it is 30.01 g/mol
2. It could also be (CH3)2 or ethane.
The molecular mass is 2*12+ 6*1= 30 g/mol
But if we search the exact weight, it
is 30.07 g/mol.
<span>So we could say it more likely to to be (CH3)2 </span>
First, we need to compute the mass of oxygen found in 100 grams of saltpeter:
mass of oxygen = 100 - (mass of potassium + mass of nitrogen)
= 100 - (38.67 + 13.86)
= 100 - 52.53
mass of oxygen in 100 grams saltpeter = 47.47 grams
Now, we can use cross multiplication to find the mass of oxygen in 328 grams saltpeter as follows:
mass of oxygen = (328 x 47.47) / 100 = 155.7016 grams
Answer:
Every sample of a given substance has identical intensive properties because every sample has the same composition
Answer: 0.4 moles
Explanation:
Given that:
Volume of gas V = 11L
(since 1 liter = 1dm3
11L = 11dm3)
Temperature T = 25°C
Convert Celsius to Kelvin
(25°C + 273 = 298K)
Pressure P = 0.868 atm
Number of moles N = ?
Note that Molar gas constant R is a constant with a value of 0.00821 atm dm3 K-1 mol-1
Then, apply ideal gas equation
pV = nRT
0.868atm x 11dm3 = n x (0.00821 atm dm3 K-1 mol-1 x 298K)
9.548 atm dm3 = n x 24.47atm dm3mol-1
n = (9.548 atm dm3 / 24.47atm dm3 mol-1)
n = 0.4 moles
Thus, there are 0.4 moles of the gas.
