At STP one mol weighs 22.4L
Moles of O_2
1 mol.O_2 can create 2mol water
moles of water
Volume of water
117.22 g are needed to react with an excess of Fe2O3 to produce 156.2 g of Fe.
Explanation:
Moles of Fe = Mass of Fe in grams / Atomic weight of Fe
= 156.2 / 55.847
Moles of Fe = 2.79.
The ratio between CO and Fe id 3 : 2.
Moles CO needed = 2.79 * (3 / 2)
= 4.185.
To calculate Atomic weight of CO,
Atomic weight of carbon = 12.011
Atomic weight of oxygen= 15.9994
Atomic weight of CO = 12.011 + 15.9994 = 28.01 g / mol.
Mass of CO = 4.185 * 28.01 = 117.22 g.
Answer:
The temperature remains
Explanation:
The temperature of a boiling substance remains the same because the extra energy is used in phase transition, that is to break the bonds between the molecules that hold them close together in the liquid state. With increased energy the molecules gain enough kinetic energy to overcome inter-molecular forces and change state from liquid to gas
the answer is 0.0693769. 6.02x10^21 x6.94/ 6.022x10^23 is the formua you would use.
