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3 years ago

Help me asap wil mark crown i always doooooooo :D

Mathematics

2 answers:

Alexus [3.1K]3 years ago

4 0

Answer:

The answer is the 1st one.

Step-by-step explanation:

Hope it helps! :)

Burka [1]3 years ago

4 0

Answer:

the answer is the first one

Step-by-step explanation:

hope this help :) :)

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Based on past experience, the main printer in a university computer centre is operating properly 90% of the time. Suppose inspec

yaroslaw [1]

Answer:

a) 38.74% probability that the main printer is operating properly for exactly 9 inspections.

b) Approximately 100% probability that the main printer is operating properly for at least 3 inspections.

c) The expected number of inspections in which the main printer is operating properly is 9.

Step-by-step explanation:

For each inspection, there are only two possible outcomes. Either it is operating correctly, or it is not. The probability of the printer operating correctly for an inspection is independent of any other inspection, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Based on past experience, the main printer in a university computer centre is operating properly 90% of the time.

This means that $p = 0.9$

Suppose inspections are made at 10 randomly selected times.

This means that $n = 10$

A) What is the probability that the main printer is operating properly for exactly 9 inspections.

This is $P(X = 9)$ . So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 9) = C_{10,9}.(0.9)^{9}.(0.1)^{1} = 0.3874$

38.74% probability that the main printer is operating properly for exactly 9 inspections.

B) What is the probability that the main printer is operating properly for at least 3 inspections?

This is:

$P(X \geq 3) = 1 - P(X < 3)$

In which

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{10,0}.(0.9)^{0}.(0.1)^{10} \approx 0$

$P(X = 1) = C_{10,1}.(0.9)^{1}.(0.1)^{9} \approx 0$

$P(X = 2) = C_{10,2}.(0.9)^{2}.(0.1)^{8} \approx 0$

Thus:

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0 + 0 + 0 = 0$

Then:

$P(X \geq 3) = 1 - P(X < 3) = 1 - 0 = 1$

Approximately 100% probability that the main printer is operating properly for at least 3 inspections.

C) What is the expected number of inspections in which the main printer is operating properly?

The expected value for the binomial distribution is given by:

$E(X) = np$

In this question:

$E(X) = 10(0.9) = 9$

3 0

3 years ago

The sneakers shown normally costs $125. Today it is on sale for 30% off. Find the sale price.

Maurinko [17]

Answer:

That answer is $37.50

Step-by-step explanation:

You havr to multiply the 125 by .30

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2 years ago

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3 gallons But in pints

MakcuM [25]

Answer: 24 pints

Step-by-step explanation:

multiply the volume value by 8

3*8=24

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3 years ago

Is (1,3) a solution of y = 3x2?

pickupchik [31]

No this is the awnser-3x+y=2

8 0

2 years ago

18 POINTS WILL GIVE BRAINLIEST !!

lys-0071 [83]

Answer:

Step-by-step explanation:

The interior triangle has a right angle, and one of its corners is 62, so the other angle, which is vertical to x, is 180-(90+62)=28, so x=28.

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3 years ago

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