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Margarita [4]
3 years ago
10

A sample of argon gas has a volume of 6 liters at a temperature of 7*C. What volume does the gas occupy at 147*C?

Physics
1 answer:
Nady [450]3 years ago
8 0

9L

Explanation:

Given parameters:

Volume of gas = 6L

Initial Temperature = 7°C to kelvin = 273 + 7 = 280K

Final temperature = 147°C to kelvin = 273 + 147 = 420K

Unknown:

Final gas volume = ?

Solution:

To solve this problem, we are going to use Charles's law. Charles's law states that "the volume of a fixed mass of a gas varies directly as its absolute temperature if the pressure is constant".

 Mathematically;

   \frac{Initial volume }{Initial temperature }  = \frac{final volume }{final temperature}

Input the parameters;

   \frac{6}{280}  = \frac{V}{420}

  V = \frac{6 x 420}{280} = 9L

learn more:

Charles's law brainly.com/question/7434588

#learnwithBrainly

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Answer:

1.69 T

Explanation:

Applying,

F = BvqsinФ.................. Equation 1

Where F = Force, B = magnetic field, v = velocity, q = charge on an electron, Ф = angle between the electron and the field.

make B the subject of the equation,

B = F/(vqsinФ)............. Equation 2

From the question,

Given: F = 2.0×10⁻¹³ N, v = 7.4×10⁵ m/s, Ф = 90°

Constant: q = 1.60×10⁻¹⁹ C

Substitute into equation 2

B =  2.0×10⁻¹³/(7.4×10⁵×1.60×10⁻¹⁹×sin90°)

B = 0.169×10

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4 0
3 years ago
Suppose a moving car has 2000 J of kinetic energy. If the carʹs speed doubles, how much kinetic energy would it then have?
Bond [772]

Answer:

option A

Explanation:

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Kinetic energy of the car = 2000 J

speed of the car is doubled

we know,

KE_1 = \dfrac{1}{2}mv^2

2000= \dfrac{1}{2}mv^2........(1)

now, speed of the car is doubled

v' = 2 v

KE_2 = \dfrac{1}{2}mv'^2

KE_2 = \dfrac{1}{2}m(2v)^2

from equation (1)

KE_2 = 4\times \dfrac{1}{2}m(v)^2

KE_2 = 4\times 2000

KE_2 = 8000\ J

Hence, the Kinetic energy would be equal to 8000 J.

The correct answer is option A.

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Is the following nuclear reaction balanced? Need answered ASAP!
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The correct answer would be yes

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Check the attached file for the answer.

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The starter motor of a car engine draws a current of 140A from the battery. The copper wire to the motor runs for 0.90s until th
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"1 Ampere" (A) means "1 coulomb of charge per second"

140 A means 140 coulombs per second

(140 coulomb/sec) x (0.9 sec)  =  126 coulombs of charge.


Go a little farther:

Electrons are the things that move through wire carrying charge.

6.25 x 10¹⁸ electrons carry 1 coulomb of charge. 

126 coulombs = 787,500,000,000,000,000,000 electrons (rounded)
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