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Margarita [4]
3 years ago
10

A sample of argon gas has a volume of 6 liters at a temperature of 7*C. What volume does the gas occupy at 147*C?

Physics
1 answer:
Nady [450]3 years ago
8 0

9L

Explanation:

Given parameters:

Volume of gas = 6L

Initial Temperature = 7°C to kelvin = 273 + 7 = 280K

Final temperature = 147°C to kelvin = 273 + 147 = 420K

Unknown:

Final gas volume = ?

Solution:

To solve this problem, we are going to use Charles's law. Charles's law states that "the volume of a fixed mass of a gas varies directly as its absolute temperature if the pressure is constant".

 Mathematically;

   \frac{Initial volume }{Initial temperature }  = \frac{final volume }{final temperature}

Input the parameters;

   \frac{6}{280}  = \frac{V}{420}

  V = \frac{6 x 420}{280} = 9L

learn more:

Charles's law brainly.com/question/7434588

#learnwithBrainly

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Consider a collection of charges in a given region and suppose all other charges are distant and have a negligible effect. Furth
AlladinOne [14]

Answer:

E. Some charges in the region are positive, and some are negative.

Explanation:

Electric potential is given as;

V = \frac{W}{Q}

where;

W is the work done in moving a charge between two points which have a difference in potential

Q is quantity of charge in the given region

If the electric potential at a given point in the region is zero, then sum of the charges in the given region must be equal to zero. For the charges to sum to zero, some will be positive while some will be negative,.

Therefore, the correct statement in the given options is "E"

E. Some charges in the region are positive, and some are negative.

3 0
3 years ago
How long will your trip take if you travel 4000 m at an average speed of 8m/s
SpyIntel [72]
  • Answer:

<em>500 sec</em>

<em>8 min 20 sec</em>

  • Explanation:

<em>Hi there !</em>

<em />

<em>8 m ................ 1 s </em>

<em>4000 m ........ x s</em>

<em>x = 4000m×1s/8m = 500 sec = 8 min 20 sec</em>

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<em>Good luck ! </em>

8 0
3 years ago
Read 2 more answers
What is the reflectivity of a glass surface (n =1.5) in air (n = 1) at an 45° for (a) S-polarized light and (b) P-polarized ligh
Goshia [24]

Answer:

a) R_s = 0.092

b) R_p = 0.085

Explanation:

given,

n =1.5 for glass surface

n = 1 for air

incidence angle = 45°

using Fresnel equation of reflectivity of S and P polarized light

R_s=\left | \dfrac{n_1cos\theta_i-n_2cos\theta_t}{n_1cos\theta_i+n_2cos\theta_t} \right |^2\\R_p=\left | \dfrac{n_1cos\theta_t-n_2cos\theta_i}{n_1cos\theta_t+n_2cos\theta_i} \right |^2

using snell's law to calculate θ t

sin \theta_t = \dfrac{n_1sin\theta_i}{n_2}=\dfrac{sin45^0}{1.5}=\dfrac{\sqrt{2}}{3}

cos \theta_t =\sqrt{1-sin^2\theta_t} = \dfrac{sqrt{7}}{3}

a) R_s=\left | \dfrac{\dfrac{1}{\sqrt{2}}-\dfrac{1.5\sqrt{7}}{3}}{\dfrac{1}{\sqrt{2}}+\dfrac{1.5\sqrt{7}}{3}} \right |^2

R_s = 0.092

b) R_p=\left | \dfrac{\dfrac{\sqrt{7}}{3}-\dfrac{1.5}{\sqrt{2}}}{\dfrac{\sqrt{7}}{3}+\dfrac{1.5}{\sqrt{2}}} \right |^2

R_p = 0.085

3 0
3 years ago
A 2.3 kg block of copper is heated at atmospheric pressure such that its temperature increases from 6 oC to 90 oC. How much heat
Shtirlitz [24]

Answer:

the  heat absorbed by the block of copper is 74368.476J

Explanation:

Hello!

To solve this problem use the first law of thermodynamics that states that the heat applied to a system is the difference between the initial and final energy considering that the mass and the specific heat do not change so we can infer the following equation

Q=mCp(T2-T1)

Where

Q=heat

m=mass=2.3kg

Cp=0.092 kcal/(kg C)=384.93J/kgK

T2=Final temperatura= 90C

T1= initial temperature=6 C

solving

Q=(2.3kg)(384.93\frac{J}{kgC} )(90C-6C)=74368.476J

the  heat absorbed by the block of copper is 74368.476J

7 0
3 years ago
Which statement describes a scientific law
Olegator [25]

The Earth is a sphere is a statement to describe a scientific law

8 0
2 years ago
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