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3 years ago

A sample of argon gas has a volume of 6 liters at a temperature of 7C. What volume does the gas occupy at 147C?

Physics

1 answer:

Nady [450]3 years ago

8 0

Explanation:

Given parameters:

Volume of gas = 6L

Initial Temperature = 7°C to kelvin = 273 + 7 = 280K

Final temperature = 147°C to kelvin = 273 + 147 = 420K

Unknown:

Final gas volume = ?

Solution:

To solve this problem, we are going to use Charles's law. Charles's law states that "the volume of a fixed mass of a gas varies directly as its absolute temperature if the pressure is constant".

Mathematically;

$\frac{Initial volume }{Initial temperature } = \frac{final volume }{final temperature}$

Input the parameters;

$\frac{6}{280} = \frac{V}{420}$

V = $\frac{6 x 420}{280}$ = 9L

learn more:

Charles's law brainly.com/question/7434588

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A sample of an ideal gas initially occupies a volume of 6 L. The pressure of the sample is then doubled while it is cooled to on

Troyanec [42]

Answer:

V₂= 1 L

Explanation:

Given that

Volume occupies V₁= 6 L

Initial pressure = P₁

Initial temperature = T₁

The final pressure =P₂ = 2 P₁

Final volume =V₂

Final temperature = T₁/3

As we know that equation for ideal gas

P V = m R T

P=pressure, V=volume, T=temperature

m=mass ,R=gas constant

Now from mass conservation

$m=\dfrac{P_1V_1}{RT_1}=\dfrac{P_2V_2}{RT_2}$

$\dfrac{P_1V_1}{RT_1}=\dfrac{P_2V_2}{RT_2}$

$\dfrac{P_1\times 6}{RT_1}=3\times \dfrac{2P_1V_2}{RT_1}$

6 = 3 x 2 V₂

V₂= 1 L

So the final volume will be 1 L

4 0

3 years ago

A cue ball has a mass of 0.5 kg. During a game of pool, the cue ball is struck and now has a velocity of 3 . When it strikes a s

photoshop1234 [79]

Answer: 3 m/s

Explanation:

We can solve the problem by using the law of conservation of momentum: during the collision between the two balls, the total momentum of the system before the collision and after the collision must be conserved:

$p_i = p_f$