A bowling ball accidentally falls out of the cargo bay of an airliner as it flies along in a horizontal direction. As seen from
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Answer:
The Initial vertical velocity is zero
Explanation:
Given that,
A book is pushed with an initial horizontal velocity, Vx = 5 m/s
According to projectile motion, the horizontal component of velocity i.e., in X-axis remains the same though out its path.
The vertical velocity varies i.e., the velocity towards the Y- axis.
The velocity of the falling book in its trajectory is the resultant velocity. Due to the action of gravity, it keeps on increasing with time.
The resultant velocity is given by relation
where
gt = Vy - vertical velocity
g - acceleration due to gravity
t - time
Since, the initial horizontal velocity at that instant is equal to the resultant velocity.
Vx = 5 m/s
= 5 m/s
So, on substituting in the above equation
Vy = 0 m/s
Therefore, the initial vertical velocity is equal to zero
Answer:
F= 5195.625 N
Explanation:
To obtain the force needed to hold the child, we need to know the aceleration in which the car is breaking.
Aceleration is equal to velocity divided by the time of breaking
In international system, velocity [m/s] is
v= (62 mi/h)*(1609 m/mi)*(1 h/3600 s)
v= 27.71 m/s
Now, we part the velocity by the time that is 0.08 seconds
a= v/t= (27.71 m/s)/(0.08 s)
a= 346.375 m/
The force in agreement with the Newton's second law is
F=m*a = 15 Kg*346.375 m/
F= 5195.625 N
(Note: 1 N = 1 Kg*m/)