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2 years ago

the four forces shown have the same strength. which force would be most effective in opening the door?

1 answer:

4 0

Hey There! According to science, if the same forces are applied, than the door will not move due to similar strength. So, regardless the door won't move. Have A Brainly Day!

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Which of the following waves have the longest wavelengths?

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Radio waves have the longest wavelengths

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3 years ago

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a scientists collects a core sample from 60 km deep in earth what will she most likley observe plz help taking a test

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Answer:

Explanation:

A scientist collects a core sample from 60 km deep in Earth. Which characteristic will she most likely observe in this sample? C. The sample mainly consists of ...

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2 years ago

Rick is moving a wheelbarrow full of bricks out to the curb. The bricks in the wheelbarrow weigh more than Rick is able to carry

USPshnik [31]

Answer is given below

Explanation:

This is happen because here when Rick walks with full loaded wheelbarriow of bricks, he able to move it because Rick lifts the wheelbarrow handle
So, most of the weight of full loaded wheelbarrow's load goes on that's wheel and due to friction force between wheel and surface it can easy to move
He uses force to rotate the wheel, much more than the force applied to the rim of the wheel on the axis of rotation or torque

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2 years ago

The edge of a flying disc with a radius of 0.13 m spins with a tangential speed of 3.3 m/s. The centripetal acceleration of the

Marat540 [252]

Answer:

Centripetal acceleration = 83.77m/s²

Explanation:

Given the following data;

Radius, r = 0.13m

Velocity, v = 3.3m/s

To find centripetal acceleration;

Centripetal acceleration is given by the formula;

$Acceleration, a = \frac {v^{2}}{r}$

Substituting into the equation, we have;

$Centripetal \; acceleration, a = \frac {3.3^{2}}{0.13}$

$Centripetal \; acceleration, a = \frac {10.89}{0.13}$

Centripetal acceleration = 83.77m/s²

Therefore, the centripetal acceleration of the edge of the disc is 83.77 m/s².

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2 years ago

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The only force acting on a 3.0 kg canister that is moving in an xy plane has a magnitude of 5.0 N. The canister initially has a

bekas [8.4K]

Answer:

The work done on the canister by the 5.0 N force during this time is

54.06 Joules.

Explanation:

Let the initial kinetic energy of the canister be

KE₁ = $\frac{1}{2} mv_1^{2}$ = $\frac{1}{2} *3*3.6^{2}$ = 19.44 J in the x direction

Let the the final kinetic energy of the canister be

KE₂ = $\frac{1}{2} mv_2^{2}$ = $\frac{1}{2} *3*7.0^{2}$ = 73.5 J in the y direction

Therefore from the Newton's first law of motion, the effect of the force is the change of momentum and the difference in energy between the initial and the final

= 73.5 J - 19.44 J = 54.06 J

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2 years ago

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