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mamaluj [8]
3 years ago
9

the four forces shown have the same strength. which force would be most effective in opening the door?

Physics
1 answer:
Umnica [9.8K]3 years ago
4 0
Hey There! According to science, if the same forces are applied, than the door will not move due to similar strength. So, regardless the door won't move. Have A Brainly Day!
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2 years ago
In ce stare mecanica este un televizor fata de masina
prisoha [69]
In what language are you speaking?
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A force of F = (2.00ˆi + 3.00ˆj) N is applied to an object that is pivoted about a fixed axle aligned along the z coordinate axi
Vladimir [108]

Explanation:

It is given that,

Force applied to object, F=(2i+3j)\ N

Position, r=(4i+5j)\ m  

(b) The cross product of force and position vector is used to find the net torque about the z axis. It is given by :

\tau=F\times r

\tau=(2i+3j) \times (4i+5j)

\tau=\begin{pmatrix}0&0&-2\end{pmatrix}

or

\tau=(-2k)\ N-m

The torque is acting in -z axis.

(a) The magnitude of torque is given by :

|\tau|=\sqrt{(-2)^2}

|\tau|=2\ N-m

Hence, this is the required solution.

5 0
3 years ago
What is necessary for a substance to be a conductor of electricity?
Stella [2.4K]
The main requirement for a good conductor of electricity is to have a lot of valence electrons. Valence electrons are the electrons of the outer shells of atoms not bound with other atoms (for example through covalent bounds). These electrons are "free to escape" as soon as an electric field with enough intensity is applied to the material, and therefore these electrons will be free to move in the material producing an electric current.
3 0
3 years ago
Air at 400 kPa, 980 K enters a turbine operating at steady state and exits at 100 kPa, 670 K. Heat transfer from the turbine occ
Angelina_Jolie [31]

Answer:

a). \frac{\dot{W}}{m}= 311 kJ/kg

b). \frac{\dot{\sigma _{gen}}}{m}=0.9113 kJ/kg-K

Explanation:

a). The energy rate balance equation in the control volume is given by

\dot{Q} - \dot{W}+m(h_{1}-h_{2})=0

\frac{\dot{Q}}{m} = \frac{\dot{W}}{m}+m(h_{1}-h_{2})

\frac{\dot{W}}{m}= \frac{\dot{Q}}{m}+c_{p}(T_{1}-T_{2})

\frac{\dot{W}}{m}= -30+1.1(980-670)

\frac{\dot{W}}{m}= 311 kJ/kg

b). Entropy produced from the entropy balance equation in a control volume is given by

\frac{\dot{Q}}{T_{boundary}}+\dot{m}(s_{1}-s_{2})+\dot{\sigma _{gen}}=0

\frac{\dot{\sigma _{gen}}}{m}=\frac{-\frac{\dot{Q}}{m}}{T_{boundary}}+(s_{2}-s_{1})

\frac{\dot{\sigma _{gen}}}{m}=\frac{-\frac{\dot{Q}}{m}}{T_{boundary}}+c_{p}ln\frac{T_{2}}{T_{1}}-R.ln\frac{p_{2}}{p_{1}}

\frac{\dot{\sigma _{gen}}}{m}=\frac{-30}{315}+1.1ln\frac{670}{980}-0.287.ln\frac{100}{400}

\frac{\dot{\sigma _{gen}}}{m}=0.0952+0.4183+0.3978

\frac{\dot{\sigma _{gen}}}{m}=0.9113 kJ/kg-K

5 0
3 years ago
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