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4 years ago

the four forces shown have the same strength. which force would be most effective in opening the door?

1 answer:

4 0

Hey There! According to science, if the same forces are applied, than the door will not move due to similar strength. So, regardless the door won't move. Have A Brainly Day!

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What is the color of visible light of the lowest frequencies? Of the highest frequencies?

Vikentia [17]

highest - violet

lowest - red

3 0

3 years ago

Read 2 more answers

A Cat is on a balcony floor (90cm below the railing), keenly eyeing a butterfly hovering 60 cm above the railing. With what spee

GenaCL600 [577]

We will have the following:

First, the equation to use is the following:

$d=v_ot+\frac{1}{2}at^2$

Now, we transform the total distance the cat would need to travel:

$90\operatorname{cm}+60\operatorname{cm}=150\operatorname{cm}\cdot\frac{1m}{100\operatorname{cm}}=1.5m$

So, the cat would need to travel 1.5 meters. ("d" in the equation).

Now, using the speed given we determine the time it would take the cat to traverse the 1.5 meters:

$t=\frac{1.5m\cdot1s}{0.45m}\Rightarrow t=\frac{10}{3}\Rightarrow t=3.333\ldots$

So, the time it would take the cat to traverse the distance will be approximately 3.33 seconds.

Now, we know that the acceleration will be given by Earth's gravity, so:

$1.5m=v_0(\frac{10}{3}s)+\frac{1}{2}(-\frac{9.8m}{s^2})(\frac{10}{3}s)^2\Rightarrow1.5m=v_0(\frac{10}{3}s)+(-\frac{490}{9}m)$ $\Rightarrow\frac{1007}{18}m=v_0(\frac{10}{3}s)\Rightarrow v_0=\frac{1007}{60}\frac{m}{s}\Rightarrow v_0=16.78333\ldots$

So, the initial vvelocity the cat must leave the floor in order to arrive at the butterfly with the optimum pouncing speed of 0.45 m/s is approximately 16.78 m/s or exactly 1007/60 m/s.

5 0

2 years ago

At the bottom of a large cylindrical tank filled with fresh water the gauge pressure is 11.6 psi. What is the height (in feet) o

Art [367]

Answer:

8.19m

Explanation:

Parameters given:

Pressure, P= 11.6 psi = 79979.185 Pa

Gauge pressure is given as:

P = h*d*g

=> h = P/(d*g)

Where

h = height of tank

d = density

g = acceleration due to gravity

Density of water = 997 kg/m³

Therefore, the height of the tank is:

h = 79979.185/(997 * 9.8)

h = 8.19m

3 0

3 years ago

The car has a constant deceleration of 4.20 m/s^2. If its initial velocity was 24.0 m/s, how long does it take to come to a stop

nalin [4]

Answer:

The time is 5.71 sec.

Explanation:

Given that,

Acceleration $a= -4.20 m/s^2$

Initial velocity = 24.0 m/s

We need to calculate the time

Using equation of motion

v = u+at[/tex]

Where, v = final velocity

u = inital velocity

t = time

a = acceleration

Put the value into the formula

$0 =24.0 +(-4.20)\times t$

$t = \dfrac{-24.0}{-4.20}$

$t=5.71\ sec$

Hence, The time is 5.71 sec.

5 0

4 years ago

Please help with this physics question

mr_godi [17]

The correct answer is A continúe moving with constant velocity

5 0

3 years ago