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Simora [160]
3 years ago
12

Plz help me with this question

Mathematics
1 answer:
Paul [167]3 years ago
8 0

Answer:

According to the graph, the answer would be the 5th month leading with 18 keychains but since I don't see that as an answer choice in the picture you provided, the answer would be the 4th month trailing close behind with a total of 16 keychains.

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Gentry poured 23.5 ounces of milk and 7.75 ounces of cream in a mixing bowl.
denpristay [2]
Notice that because the capacity of the bowl is 35.5 ounces, but there has already been 31.25 ounces total added to it (23.5 ounces + 7.75 ounces), all that needs to be done is subtract 31.25 from 35.5:
35.5 - 31.25 = 4.25 ounces of cream could be added
4 0
3 years ago
Help please here is a picture:
Ivahew [28]

Answer:

<em>2 1/3, 2 1/4, 2 3/7</em>

Step-by-step explanation:

<u>Mixed Fractions</u>

Mixed fractions are made of an integer part followed by a proper fraction.

Some examples of mixed fractions are:

3 1/2, -4 5/8, 2 2/3

Between two consecutive integers a and a+1, there are infinitely many fractions. The centered number is a 1/2. Any number with its improper fraction part less than 1/2 is closer to a than to a+1.

In our problem, Jayne bought between 2 and 3 pounds of granola. We need to provide a mixed number that is closer to 2 pounds than to 3 pounds.

We can select any number with integer part 2 and a proper fraction less than 1/2.

Examples could be :

2 1/3, 2 1/4, 2 3/7

All of them are less than 2.5

6 0
3 years ago
What is the equation of the line x–3y=18x–3y=18 in slope-intercept form?
Liono4ka [1.6K]
The correct answer is y= -18/3x
7 0
3 years ago
A manufacturing plant earned $80 per man-hour of labor when it opened. Each year, the plant earns an additional 5% per man-hour.
baherus [9]

A function that gives the amount that the plant earns per man-hour t years after it opens is \mathrm{A}(\mathrm{t})=80 \times 1.05^{\mathrm{t}}

<h3><u>Solution:</u></h3>

Given that  

A manufacturing plant earned $80 per man-hour of labor when it opened.

Each year, the plant earns an additional 5% per man-hour.

Need to write a function that gives the amount A(t) that the plant earns per man-hour t years after it opens.  

Amount earned by plant when it is opened = $80 per man-hour

As it is given that each year, the plants earns an additional of 5% per man hour

So Amount earned by plant after one year = $80 + 5% of $80 = 80 ( 1 + 0.05) = (80 x 1.05)

Amount earned by plant after two years is given as:

=(80 \times 1.05)+5 \% \text { of }(80 \times 1.05)=(80 \times 1.05)(1.05)=80 \times 1.052

Similarly Amount earned by plant after three years =80 \times 1.05^{t}

\begin{array}{l}{\Rightarrow \text { Amount earned by plant after } t \text { years }=80 \times 1.05^{t}} \\\\ {\Rightarrow \text { Required function } \mathrm{A}(t)=80 \times 1.05^{t}}\end{array}

Hence a function that gives the amount that the plant earns per man-hour t years after it opens is \mathrm{A}(t)=80 \times 1.05^{t}

5 0
3 years ago
Solve (2x3-5x2+8)(x+3)
neonofarm [45]

Answer:

(2 {x}^{3}  - 5 {x}^{2}  + 8)(x + 3) \\  = (2 {x}^{4}  - 5 {x}^{3}  + 8x + 6 {x}^{3}  - 15 {x}^{2}  + 24) \\  = 2 {x}^{4}  +  {x}^{3}  - 15 {x}^{2}  + 8x + 24

8 0
2 years ago
Read 2 more answers
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