Answer:
No its is the oxidation half
Explanation:
Because Pb lost
and oxidation is losing, I abbreviate it in (OIL) not oil that used in kitchen
OIL=Oxidation Is Losing electrons
Answer:
Relative error = 0.35
observed value = 8.775
Explanation:
given data:
Actual value = 13.5 L
Percentage of error=35%
Relative error can be determined as follow:
![Relative\ error = \frac{absolute\ error}{actual\ value}](https://tex.z-dn.net/?f=Relative%5C%20error%20%3D%20%5Cfrac%7Babsolute%5C%20error%7D%7Bactual%5C%20value%7D)
Absolute error = actual value - observed value
Percentage of error ![= relative error*100](https://tex.z-dn.net/?f=%3D%20relative%20error%2A100)
Then relative error ![= \frac{percentage\ of\ error}{100}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7Bpercentage%5C%20of%5C%20error%7D%7B100%7D%20)
Relative error ![= \frac{35}{100} =0.35](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B35%7D%7B100%7D%20%3D0.35)
Then absolute error = ![relative\ error\times actual\ value](https://tex.z-dn.net/?f=relative%5C%20error%5Ctimes%20actual%5C%20value)
![=0.35\times 13.5 = 4.725](https://tex.z-dn.net/?f=%3D0.35%5Ctimes%2013.5%20%3D%204.725)
Therefore experimental measurement value(observed value)
= actual value - absolute error
=13.5 - 4.725 = 8.775
<u>Answer:</u> The atomic mass of carbon is 12 amu and that of carbon dioxide is 44 g/mol
<u>Explanation:</u>
Molar mass is defined as the sum of the mass of all the atoms each multiplied its atomic masses that are present in the molecular formula of a compound. It is expressed in g/mol.
We know that:
Atomic mass of carbon = 12 amu
We are given a chemical compound, carbon dioxide having chemical formula of ![CO_2](https://tex.z-dn.net/?f=CO_2)
Molar mass of carbon = 12 g/mol
Molar mass of oxygen = 16 g/mol
Evaluating the molar mass of carbon dioxide, we get:
Molar mass of ![CO_2=[12+(2\times 16)]=44g/mol](https://tex.z-dn.net/?f=CO_2%3D%5B12%2B%282%5Ctimes%2016%29%5D%3D44g%2Fmol)
Hence, the atomic mass of carbon is 12 amu and that of carbon dioxide is 44 g/mol
Answer: 10.63
Explanation: You divide the mass by volume.