Answer:
Explanation:
The products of this reaction are given by:
Firstly, dichromate anion becomes chromium(III) cation, let's write this change:
The following steps should be taken:
- balance the main element, chromium: multiply the right side by 2 to get 2 chromium species on both side:
- balance oxygen atoms by adding 7 water molecules on the right:
- balance the hydrogen atoms by adding 14 protons on the left:
- balance the charge (the total net charge on the left is 12+, on the right we have 6+, so 6 electrons are needed on the left):
Similarly, tin(II) cation becomes tin(IV) cation:
Now that we have the two half-equations, multiply the second one by 3, so that it also has 6 electrons that will be cancelled out upon addition of the two half-equations:
Add them together:
Adding the ions spectators:
The reaction between C2H2 and O2 is as follows:
2C2H2 + 5O2 = 4CO2 + 2H2O
After balancing the equation, the reaction ratio between C2H2 and O2 is 2:5.
The moles of O2 in this reaction is 84.0 mol. According to the above ratio, the moles of C2H2 needed to react completely with the O2 is 84.0mole *2/5 = 33.6 mole.
Answer:
Option-A (<span> It would increase from bottom left to top right) is the correct answer.
Explanation:
As we know converting solids into liquids and converting liquids into gases require energy. This energy provided increases the energy of the state and its particles start moving with higher velocities. Therefore, the energy of solids will be lower than liquids and gases respectively. While, liquids have greater energy than solids but less energy than gases. And, gases are the most energetic than solids and liquids.</span>
This problem is providing two reduction-oxidation (redox) reactions in which the oxidized and reduced species can be identified by firstly setting the oxidation number of each element:
Reaction 1: 2K⁺I⁻ + H₂⁺O₂⁻ ⇒2K⁺O⁻²H⁺ + I₂⁰
Reaction 2: Cl₂⁰ + H₂⁰ ⇒ 2H⁺CI⁻
Next, we can see that iodine is being oxidized and oxygen reduced in reaction #1 and chlorine is being reduced and hydrogen oxidized in reaction #2 because the oxidized species increase the oxidation number whereas the reduced ones decrease it.
In such a way, the correct choice is C.
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B) A chemical change because the nail reacts with water/oxygen to create rust (a type of oxide)
