The radon-222 sample has a half-life of 3.8 days, and we are asked how many times would the mass divide in half after 23 days. First we calculate the amount of times division occurs by taking the number of days and dividing that by the number of days for one half-life to occur: 23/3.8 = 6.05.
We have 198.6 grams of sample, and we are going to divide it in half 6 times to determine how much of it remains after 23 days:
198.6/2 = 99.3 grams
99.3/2 = 49.65 grams
49.65/2 = 24.83 grams
24.83/2 = 12.41 grams
12.41/2 = 6.21 grams
6.21/2 = 3.1 grams
Therefore, we are left with 3.1 grams of radon-222 after 23 days if one half-life equals to 3.8 days.
Answer:
I don't know and I don't understand
Explanation:
I don't know and I don't understand
sorry
sorry for not being able to answer your question
Answer:
Q < Ksp
Explanation:
The general equilibrium of a constant product solubility, ksp, is:
AB ⇄ A⁺ + B⁻
<em>Where Ksp is defined as:</em>
Ksp = [A⁺] [B⁻]
When [A⁺] [B⁻] = Ksp, the solution is saturated or oversaturated because there are the maximum amount of ions that solution can dissolve.
When the solution is oversaturated, AB is produced.
Now, in a unsaturated solution, the [A⁺] [B⁻] is less than the maximum amount that can be dissolved. That means:
[A⁺] [B⁻] = Q < Ksp
Q is defined in the same way than Ksp, just in Q the system is not in equilibrium.
Right answer is:
<h3>Q < Ksp</h3>
