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True [87]
2 years ago
15

Calculate the freezing point of a solution that contains 8.0 g of sucrose (C12H22O11) in 100 g of H2O. Kf for H2O = 1.86C/m

Chemistry
1 answer:
Aleks04 [339]2 years ago
8 0

The freezing point of the sucrose solution is -0.435°C.

<h3>What is the freezing point of the solution?</h3>

The freezing point of the solution is determined from the freezing point depression formula below:

  • ΔT = mKf(H₂O)

Kf(H₂O) = 1.86 Cm

m is molality of solution = moles of solute/mass of solvent

moles of sucrose = 8.0/342.3 = 0.0233 moles

m = 0.0233/0.1 = 0.233 molal

ΔT = 0.233 m * 1.86°C/m.

ΔT = 0.435 °C.

Freezing point of sucrose solution = 0°C - 0.435°C

Freezing point of sucrose solution  = -0.435°C.

In conclusion, the freezing point of sucrose solution is determined from the freezing point depression.

Learn more about freezing point depression at: brainly.com/question/19340523

#SPJ1

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