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natita [175]
2 years ago
7

Someone help plzzzz just need final answers I’ll mark Brainly

Chemistry
1 answer:
Alex_Xolod [135]2 years ago
4 0

Answer:

Omodium

Explanation:

It’s Umodium

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Why are rocks not alive
Liula [17]

What Are Living Rocks? Rocks themselves are not alive. But in a coral reef rock-like lime substance is continually produced from the skeletons of dead rock corals and the shells of mussels and other creatures which are bound together by sponges and calcareous algae.

but tbh I have no idea lol!

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3 years ago
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Slimotosis
Flauer [41]

Answer:

Here's what I get  

Explanation:

A. Initial observation

Gary's shell had slime and an odour.

B. Independent variable

The independent variable is the one that the experimenter changes.

There are two independent variables: the rubbing with seaweed and the drinking of Dr. Kelp.

C. The dependent variable

The dependent variable is the amount of slime and odour.

D. The conclusion

Sponge Bob can conclude that rubbing the shell with seaweed and drinking Dr. Kelp removes the slime and odour.

However, this was a poorly designed experiment. He doesn't know if it is the seaweed or the Dr. Kelp that gives the result or if he must use both together. He should change only one independent variable at a time.

4 0
3 years ago
What did Ernest Rutherford discover? How was his model different from Thomson’s?
s2008m [1.1K]

Answer:

thomson developed the chocolate chip method which was the identification of the electrons in the core of an atom.  Rutherford discovered that the core was only positive and that the electrons were floating outside of the core.

Explanation:

4 0
3 years ago
PLEASE HELP!!!
Darina [25.2K]
None of the above I believe it is what can form a tornado??
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3 years ago
The half-life of cesium-137 is 30 years. Suppose we have a 200-mg sample. (a) Find the mass that remains after t years.
scZoUnD [109]

Given:

Half life(t^ 1/2) :30 years

A0( initial mass of the substance): 200 mg.

Now we know that

A= A0/ [2 ^ (t/√t)]

Where A is the mass that remains after t years.

A0 is the initial mass

t is the time

t^1/2 is the half life

Substituting the given values in the above equation we get

A= [200/ 2^(t/30) ] mg


Thus the mass remaining after t years is [200/ 2^(t/30) ] mg

5 0
3 years ago
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