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natita [175]
3 years ago
7

Someone help plzzzz just need final answers I’ll mark Brainly

Chemistry
1 answer:
Alex_Xolod [135]3 years ago
4 0

Answer:

Omodium

Explanation:

It’s Umodium

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Why is physical exercise often suggested if you experience an abundance of stress?
scoray [572]

Answer:

good question

Explanation:

probably because people like to say they know things and help people with "there stress" and think that there helping them but in reality there making it where they have more :)

4 0
3 years ago
A chocolate bar weighs 4.00 ounces. If the chocolate delivers 2.78 calories per gram, how many
dimulka [17.4K]

Answer:

40.79

Explanation:

an ounce is equal to approximately 28.3 grams.

if you have 4 ounces then it would be equal to about 113.4 grams. then you would divide that by 2.78 which will equal about 40.8

6 0
3 years ago
Which of the 4 macromolecules is the most important for a cell to carry out metabolism and maintain homeostasis?
azamat

Answer:

Carbs,lipids,proteins,nuclei acids

Explanation:

3 0
3 years ago
Final volume of Argon gas:
DerKrebs [107]

Answer:

6.78 × 10⁻³ L

Explanation:

Step 1: Write the balanced equation

Mg₃N₂(s) + 3 H₂O(g) ⇒ 3 MgO(s) + 2 NH₃(g)

Step 2: Calculate the moles corresponding to 10.2 mL (0.0102 L) of H₂O(g)

At STP, 1 mole of H₂O(g) has a volume of 22.4 L.

0.0102 L × 1 mol/22.4 L = 4.55 × 10⁻⁴ mol

Step 3: Calculate the moles of NH₃(g) formed from 4.55 × 10⁻⁴ moles of H₂O(g)

The molar ratio of H₂O to NH₃ is 3:2. The moles of NH₃ produced are 2/3 × 4.55 × 10⁻⁴ mol = 3.03 × 10⁻⁴ mol.

Step 4: Calculate the volume corresponding to 3.03 × 10⁻⁴ moles of NH₃

At STP, 1 mole of NH₃(g) has a volume of 22.4 L.

3.03 × 10⁻⁴ mol × 22.4 L/mol = 6.78 × 10⁻³ L

3 0
3 years ago
For a molecule of fluorous acid, the atoms are arranged as HOFO. (Note: In this oxyacid, the placement of fluorine is an excepti
Maksim231197 [3]

Answer:

0,0,0,0

Explanation:

The formal charge formula:

Formal charge= Valence electrons - lone pair electrons - 0.5 shared electrons

So:

Hydrogen: 1 elec. of valence and shares two electrons with the O

Formal charge= 1 - 0 - 0.5*2=0

Oxygen: 6 elec. of valence, 2 lone pairs and shares two electrons with the H and two with the F

Formal charge= 6 - 4 - 0.5*4=0

Fluorine: 7 elec. of valence, 6 lone pairs and shares two electrons with the O

Formal charge= 7 - 6 - 0.5*2=0

Oxygen: 6 elec. of valence, 3 lone pairs

Formal charge= 6 - 6 - 0.5*0=0

Note: the dative bond between F and the second O doesn't count as shared electrons.

8 0
3 years ago
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