The relationship between energy of a single photon and its wavelength can be determined using the formula E=hc/lambda where E is energy, h is Planck's constant, c is the speed of light, and lambda is photons.
Before being able to solve for energy, need to convert nanometers to meters.
407 nm (1 m/1 x 10^9 nm) = 4.07 x 10^-7 m
Then plug in the values we know into the equation.
E h(Planck's constant) c(speed of light)
E = (6.63 x 10^-34 Js)(3 x 10^8 m/s) / 4.07 x 10^-7 m (lambda)
E=(0.000000000000000000000000000000000663js)(300,000,000m/s)=1.989×10^-25j/ms
E=1.989x10^-25j/ms /{divided by} 4.07x10^-7m = 4.8869779x10^-33 J (the meters cancel out)
E = 4.89 x 10^-33 J
This gives us the energy in Joules of a single photon. Now, we can find the number of photons in 0.897 J
0.897J / 4.89 x 10^-33 J = ((0.897 J) / 4.89) x ((10^(-33)) J) = 1.8343558 x 10^-34
1.83435583 × 10-34m4 kg2 / s4 photons
They make science a thing. Science isn't just space and microbes etc. We need science to solve things in society, politics, and economics.
A-Locations M and O are at the poles.
Explanation:
Locations M and O are located at the poles because they receive sunlight that is spread out over a large surface area. The poles receive sunlight at an angle to the surface and it causes the rays of the sun to spread out in all direction.
- At the equator, sunlight impinges directly on the surface and the solar radiation here is very much.
- It is important to know that the sun is overhead directly at the equator.
- The earth is tilted at an angle to sun and therefore, areas around the polar region will receive sunlight that is spread out in different directions over a large area.
- Away from the pole, the equator is directly facing the sun and it receives direct sunlight.
Learn more:
solar radiation brainly.com/question/10940063
#learnwithBrainly
Answer:
Phenolphthalein is a chemical compound with the formula C20H14O4 and is often written as "HIn" or "phph" in shorthand notation. Phenolphthalein is often used as an indicator in acid–base titrations. For this application, it turns colorless in acidic solutions and pink in basic solutions.
