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oksian1 [2.3K]
4 years ago
14

A gardener has 27 pansies and 36 daisies he ants an equal number of each type of flower in each row what is the greatest possibl

e number of pansies in each row
Mathematics
1 answer:
Komok [63]4 years ago
5 0
There are 27 pansies.
The possible rows that will contain equal numbers of pansies are
1 row, 27 pansies in the row, or
3 rows, 9 pansies per row, or
9 rows, 3 pansies per row.

There are 36 daisies.
The possible rows that will contain equal numbers of daisies are
1 row, 36 daisies in the row,
2 rows, 18 daisies per row, or
3 rows, 12 daisies per row, or
4 rows, 9 daisies per row, or
6 rows, 6  daisies per row, or
9 rows, 4  daisies per row, or
12 rows, 3 daisies per row, or
18  rows, 2 daisies per row.

The only common row combination is 3 rows, with 9 pansies and 12 daisies per row.

Answer:  9 pansies in each row.
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Ms. Baron earns $20 for walking 4 dogs. How much would she earn for each dog?
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Step-by-step explanation:

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Nat2105 [25]

Answer:

Option B. Cosec θ = –5/3

Option C. Cot θ = 4/3

Option D. Cos θ = –4/5

Step-by-step explanation:

From the question given above, the following data were obtained:

Tan θ = 3/4

θ is in 3rd quadrant

Recall

Tan θ = Opposite / Adjacent

Tan θ = 3/4 = Opposite / Adjacent

Thus,

Opposite = 3

Adjacent = 4

Next, we shall determine the Hypothenus. This can be obtained as follow:

Opposite = 3

Adjacent = 4

Hypothenus =?

Hypo² = Opp² + Adj²

Hypo² = 3² + 4²

Hypo² = 9 + 16

Hypo² = 25

Take the square root of both side

Hypo = √25

Hypothenus = 5

Recall:

In the 3rd quadant, only Tan is positive.

Therefore,

Hypothenus = –5

Finally, we shall determine Sine θ, Cos θ, Cot θ and Cosec θ to determine which option is correct. This can be obtained as follow:

Opposite = 3

Adjacent = 4

Hypothenus = –5

Sine θ = Opposite / Hypothenus

Sine θ = 3/–5

Sine θ = –3/5

Cos θ = Adjacent / Hypothenus

Cos θ = 4/–5

Cos θ = –4/5

Cot θ = 1/ Tan θ

Tan θ = 3/4

Cot θ = 1 ÷ 3/4

Invert

Cot θ = 1 × 4/3

Cot θ = 4/3

Cosec θ = 1/ Sine θ

Sine θ = –3/5

Cosec θ = 1 ÷ –3/5

Invert

Cosec θ = 1 × –5/3

Cosec θ = –5/3

SUMMARY

Sine θ = –3/5

Cos θ = –4/5

Tan θ = 3/4

Cot θ = 4/3

Cosec θ = –5/3

Therefore, option B, C and D gives the correct answer to the question.

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