Answer:
The distance between adjacent antinodes of the standing wave is 1.25 m.
Explanation:
Given that,
Frequency f= 120 MHz
We need to calculate the distance between adjacent antinodes of the standing wave
Using formula of distance
.....(I)
We know that,
![\lambda=\dfrac{c}{f}](https://tex.z-dn.net/?f=%5Clambda%3D%5Cdfrac%7Bc%7D%7Bf%7D)
Put the value of
in to the equation (I)
![\Delta x=\dfrac{c}{2f}](https://tex.z-dn.net/?f=%5CDelta%20x%3D%5Cdfrac%7Bc%7D%7B2f%7D)
Where, c = speed of light
f = frequency
Put the all value into the formula
![\Delta x=\dfrac{3\times10^{8}}{2\times120\times10^{6}}](https://tex.z-dn.net/?f=%5CDelta%20x%3D%5Cdfrac%7B3%5Ctimes10%5E%7B8%7D%7D%7B2%5Ctimes120%5Ctimes10%5E%7B6%7D%7D)
![\Delta x=1.25\ m](https://tex.z-dn.net/?f=%5CDelta%20x%3D1.25%5C%20m)
Hence, The distance between adjacent antinodes of the standing wave is 1.25 m.
I think 8.4
i learned that magnitude 8.4 earthquake had hit japan before
Answer:
Explanation:
The fish falls from vertical rest in a time of
t = √(2h/g) = √(2(2.27)/9.81) = 0.68 s
v = d/t = 5.6 / 0.68 = 8.2 m/s
Answer:
Explanation:
so filling in:
so to 2 sig figs (which is actually not accurate, but oh well...)
KE = 450000 J
If we want to find out how high it will have to travel up a hill so that its PE is the same as the KE at this speed, we set the value for KE = to PE:
450000 = (1000)(9.8)h so
![h=\frac{450000}{(1000)(9.8)}=45.9m](https://tex.z-dn.net/?f=h%3D%5Cfrac%7B450000%7D%7B%281000%29%289.8%29%7D%3D45.9m)