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Rudik [331]
3 years ago
8

ANSWER ASAPPP

Physics
2 answers:
miv72 [106K]3 years ago
7 0

C is the correct answer

Vikki [24]3 years ago
5 0
C) fault block, the mountain is forming on a FAULT line.
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Suppose a NASCAR race car rounds one end of the Martinsville Speedway. This end of the track is a turn with a radius of approxim
Schach [20]

Complete Question

Suppose a NASCAR race car rounds one end of the Martinsville Speedway. This end of the track is a turn with a radius of approximately 57.0 m . If the track is completely flat and the race car is traveling at a constant 30.5 m/s (about 68 mph ) around the turn.

Required:

a. What is the race car's centripetal (radial) acceleration?

b. What is the force responsible for the centripetal acceleration in this case?

O normal

O gravity

O friction

O weight

Answer:

question a

       a = 16.32 \  m/s^2

question b

        correct option is option 3

Explanation:

From the question we are told that

   The radius is  r = 57.0 \ m \

    The constant speed at which the race car is travelling is v  = 30 .5 \ m/s

Generally from the question we are told that the track is completely flat so the only force pulling the car to the middle is the frictional force hence the centripetal force is due to the frictional force

    Generally the centripetal acceleration is mathematically represented as

      a = \frac{v^2}{r}

=>    a = \frac{30.5^2}{ 57}

=>    a = 16.32 \  m/s^2

6 0
3 years ago
The escape velocity at the surface of Earth is approximately 11 km/s. What is the mass, in units of ME (the mass of the Earth),
SVETLANKA909090 [29]

Answer:11 km/s

Explanation:

Given

Escape velocity at the surface of earth is 11 km/s

Escape velocity is given by

V_e=\sqrt{\frac{2GM}{R}}

Escape velocity at the surface of earth

11=\sqrt{\frac{2GM}{R}}--------------------1

If Escape velocity is three times and the radius is also the three times

V_e_2=\sqrt{\frac{2G(3M)}{3R}}

V_e_2=\sqrt{\frac{2GM}{R}}=V_e

i.e. V_e_2=11 km/s

5 0
3 years ago
What would the velocity of an object be if it was on a 1.75m
JulijaS [17]

Answer:

T = 4 sec / 2 = 2 sec      period of revolution

S = 2 pi R = 2 * pi * 1.75 m = 11 m

V = S / T = 11 m / 2 sec = 5.5 m/s       speed of object

4 0
3 years ago
Which would be the best way to represent the concentration of a 1.75 M K2CrO4 solution
AlekseyPX
1.75 moles per litre K2CrO4
7 0
4 years ago
Read 2 more answers
A force F at an angle θ above the horizontal is used to pull a heavy suitcase of weight mg a distance d along a level floor at c
Sati [7]

Answer:

option A

Explanation:

given,

Force = F

angle = θ

weight on suitcase = mg

distance = d

constant velocity so, acceleration a = 0

coefficient of friction = µ

Work done = ?

Work done is equal to force into displacement.

Friction act opposite to the force acting so, work done by frictional force will be negative.

frictional force will act into horizontal direction opposite to force.

here displacement is equal to d

now,

W = -F d cos θ

Hence,the correct answer is option A

3 0
3 years ago
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