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2 years ago

R spectroscopy can be used to identify which _____________________ are present in a compound.

Chemistry

1 answer:

Nesterboy [21]2 years ago

3 0

Answer:

IR spectroscopy can be used to identify chemical structures are present in compounds.

Explanation:

Infrared spectroscopy is a technique in organic chemistry that can be use use to identify chemical structures present in compounds because it is base on the ability of different functional groups to adsorb infrared light.

This work by shinning the infrared lights into the organic compounds to be identified, some of the frequencies of the infrared lights are adsorbed by the compounds and its identify groups of atoms and molecules in the compound.

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Substitute natural gas (SNG) is a gaseous mixture containing CH4(g) that can be used as a fuel. One reaction for the production

Lynna [10]

Answer:

ΔH° of the reaction is -747.54kJ

Explanation:

Based on gas law, it is possible to find the ΔH of a reaction using ΔH of half reactions.

Using the reactions:

(1) C(graphite) + 1/2O₂(g) → CO(g) ΔH° = -110.5 kJ

(2) CO(g) + 1/2O₂(g) → CO₂(g) ΔH° = -283.0 kJ

(3) H₂(g) + 1/2O₂(g) → H₂O(l) ΔH° = -285.8 kJ

(4) C(graphite) + 2H₂(g) → CH₄(g) ΔH° = -74.81 kJ

(5) CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(l) ΔH° = -890.3 kJ

The sum of 4×(4) + (5) gives:

4C(graphite) + 8H₂(g) + 2O₂(g) → CO₂(g) + 2H₂O(l) + 3CH₄(g)

ΔH° = -74.81 kJ ×4 - 890.3 kJ = -1189.54kJ

Now, this reaction - 4×(1) gives:

4CO(g) + 8H₂(g) → CO₂(g) + 2H₂O(l) + 3CH₄(g)

ΔH° = -1189.54kJ - 4×-110.5 = -747.54kJ

Thus ΔH° of the reaction is -747.54kJ

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3 years ago

Jupiter revolves around the sun in a predictable pattern because

Misha Larkins [42]

Jupiter revolves around the Sun in a predictable pattern because the force of gravity between Jupiter and the Sun maintains the orbit.

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2 years ago

Suppose you have 15.0 ml of zinc. What volume of aluminum would have the same mass as the zinc?

Black_prince [1.1K]

Answer:

$\large \boxed{\text{41.2 cm}^{3}}$

Explanation:

1. Mass of zinc

The density of zinc is 7.14 g/cm³

D = m/V

$\begin{array}{rcl}7.14 & = & \dfrac{m}{15.0}\\\\m & = & 7.14 \times 15.0\\& = & \text{107.1 g}\\\end{array}\\$

2. Volume of aluminium

The density of aluminium is 2.60/cm³.

$\begin{array}{rcl}2.60 & = & \dfrac{107.1}{V}\\\\2.60V & = & 107.1\\V& = &\dfrac{107.1}{2.60}\\\\& = &\textbf{41.2cm}^{\mathbf{3}}\\\end{array}\\\large \boxed{\textbf{41.2 cm}^{\mathbf{3}}}\text{ of aluminium have the same mass as 15.0 cm$^{3}$ of zinc.}$

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3 years ago

You are about to open a container of soy milk but notice that there are instructions to “shake well before serving.” the soy mil

goldenfox [79]

The soy milk is most likely a suspension.

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3 years ago

Read 2 more answers

What is the splitting of the signal in the 1H NMR spectrum for the methyl protons of 1-bromo-2-methylpropane?

Arada [10]

Answer:

doublet

Explanation:

Proton MNR is used for the determination of no. of equivalents protons in a molecule

In the molecule, single NMR signal is produced for each set of protons.

Signal splitting is called spin-spin coupling and the splitting of signals depends upon the no. of neighboring proton.

The no. of signal for a proton is equal to n+1, where n is neighboring protons.

In 1-bromo-2-methylpropane, neighboring proton for both methyl protons are one. But the chemical environment of both the methyl protons are different.

Neighboring proton for methyl protons = 1

No. of signal for methyl protons = 1+1 =2

Hence, two doublets will be generated for each set of methyl protons. protons.

3 0

3 years ago