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2 years ago

5

R spectroscopy can be used to identify which _____________________ are present in a compound.

1 answer:

Nesterboy [21]2 years ago

3 0

Answer:

IR spectroscopy can be used to identify chemical structures are present in compounds.

Explanation:

Infrared spectroscopy is a technique in organic chemistry that can be use use to identify chemical structures present in compounds because it is base on the ability of different functional groups to adsorb infrared light.

This work by shinning the infrared lights into the organic compounds to be identified, some of the frequencies of the infrared lights are adsorbed by the compounds and its identify groups of atoms and molecules in the compound.

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An elemental analysis is performed in an unknown compound. It is found to contain 40.0 % mass in Carbon, 6.71% mass in Hydrogen,

DENIUS [597]

Answer: Molecular formula will be $C_3H_6O_3$

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of C= 40 g

Mass of H = 6.71 g

Mass of O = 100 - (40+6.71 ) = 53.29 g

Step 1 : convert given masses into moles.

Moles of C = $\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{40g}{12g/mole}=3.33moles$

Moles of H = $\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{6.71g}{1g/mole}=6.71moles$

Moles of O = $\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{53.29g}{16g/mole}=3.33moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = $\frac{3.33}{3.33}=1$

For H = $\frac{6.71}{3.33}=2$

For O = $\frac{3.33}{3.33}=1$

The ratio of C: H: O= 1 : 2: 1

Hence the empirical formula is $CH_2O$

The empirical weight of $CH_2O$ = 1(12)+2(1)+1(16)= 30g.

The molecular weight = 90.08 g/mole

Now we have to calculate the molecular formula:

$n=\frac{\text{Molecular weight}}{\text{Equivalent weight}}=\frac{90.08}{30}=3$

The molecular formula will be= $3\times CH_2O=C_3H_6O_3$

Molecular formula will be $C_3H_6O_3$

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2 years ago