Answer:
<em>Your</em><em> </em><em>Answer</em><em> </em><em>is</em><em> </em><em>Option</em><em> </em><em>A</em><em> </em><em>that</em><em> </em><em>is</em><em> </em><em>Gas</em><em>.</em>
Answer:
Molecules move from areas of high concentration to areas of low concentration.
<span>NaOH + HCl = NaCl + H2O</span>
Answer: 30. 7 moles SO3
31. 3 moles SO2 and 3 moles SO3
Explanation: To solve for this problem use the mole ratio of the substances involved in the reaction.
Solution for number 30:
3.5 moles O2 x 2 moles SO3 / 1 mole O2
= 7 moles SO3
31. 192 g SO2 x 1 mole SO2 / 64 g/ mol SO2
= 3 moles SO2
3 moles SO2 x 2 moles SO3 / 2 moles SO2
= 3 moles SO3
Answer:
Hi
Williamson's ether reactions imply that an alkoxide reacts with a primary haloalkane. Alkoxides consisting of the conjugate base of an alcohol and are formed by a group R attached to an oxygen atom. They are often written as RO–, where R is the organic substituent (Step 1).
Sn2 reactions are characterized by the reversal of stereochemistry at the site of the leaving group. Williamson's synthesis is no exception and the reaction is initiated by the subsequent attack of the nucleophile. This requires that the nucleophile and electrophile be in anti-configuration (Step 2).
As an example (figure 3).
In the attached file are each of the steps of Williamson's synthesis.
Explanation:
