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ahrayia [7]
3 years ago
13

5. In a lab experiment, 45 grams of a metal are heated from 22⁰C to 78⁰C by the addition of 450 J of heat. What is the specific

heat of the metal? Show all calculations leading to an answer.
Physics
1 answer:
Anuta_ua [19.1K]3 years ago
8 0
Energy = mc (delta T) where m is the mass in kg, c is the specific heat capacity, and delta T is the change in temperature.

450 = (45x10^-3)c (78-22)

450 = (0.045)c (56)

c = 178.57 J/kgK
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3 years ago
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v_y = \dfrac{\mathrm dy}{\mathrm dt} = \left(1\dfrac{\rm m}{\mathrm s^2}\right)t-2\dfrac{\rm m}{\rm s}

At <em>t</em> = 5.0 s, the particle has velocity

v_x = \left(1.5\dfrac{\rm m}{\mathrm s^3}\right) (5.0\,\mathrm s)^2 - \left(4\dfrac{\rm m}{\mathrm s^2}\right)(5.0\,\mathrm s) = 17.5\dfrac{\rm m}{\rm s}

v_y = \left(1\dfrac{\rm m}{\mathrm s^2}\right)(5.0\,\mathrm s)-2\dfrac{\rm m}{\rm s} = 3.0\dfrac{\rm m}{\rm s}

The speed at this time is the magnitude of the velocity :

\sqrt{{v_x}^2 + {v_y}^2} \approx \boxed{17.8\dfrac{\rm m}{\rm s}}

The direction of motion at this time is the angle \theta that the velocity vector makes with the positive <em>x</em>-axis, such that

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4 0
2 years ago
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<h3>What is power?</h3>

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Learn more about Power:

brainly.com/question/1618040

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